CODEWITHSUNDEEP
bash
showkey
showkey

Reputation: 348

How to pass the result of a function as argument into a Bash function?

I have this function:

test() {
  echo "$1"
}

$1 can receive an argument. This works:

test "i am here"
i am here

Now I want to receive the result of date.

date
Tue Jan 10 10:36:10 CST 2017

test   `date`
Tue

How to make Jan 10 10:36:10 CST 2017 not be omitted?

Upvotes: 0

Views: 38

Answers (1)

codeforester
codeforester

Reputation: 42989

You need to enclose the result of date in double quotes for the entire date string to be sent as a single argument to your function:

test "`date`"

or, more preferably:

test "$(date)"

Here is an example:

$ test "$(date)"
Tue Jan 10 03:17:26 UTC 2017

Upvotes: 2

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