Reputation: 1851
I am using PySNMP to get the IPs of the CDP neighbors.
This is my current function, which works, but the output is of the type hexValue
.
def get_neighbors():
for (errorIndication,
errorStatus,
errorIndex,
values) in nextCmd(SnmpEngine(),
CommunityData('public', mpModel=0),
UdpTransportTarget((SWITCH, 161)),
ContextData(),
ObjectType(ObjectIdentity('CISCO-CDP-MIB', 'cdpCacheAddress')).addAsn1MibSource('file://asn1/CISCO-CDP-MIB'),
lexicographicMode=False, lookupNames=True, lookupValues=True):
print(values)
for v in values:
print(v)
It outputs the following:
[ObjectType(ObjectIdentity(ObjectName('1.3.6.1.4.1.9.9.23.1.2.1.1.4.10106.14')), CiscoNetworkAddress(hexValue='ac14103a'))]
CISCO-CDP-MIB::cdpCacheAddress.10106.14 = 0xac14103a
[ObjectType(ObjectIdentity(ObjectName('1.3.6.1.4.1.9.9.23.1.2.1.1.4.10125.9')), CiscoNetworkAddress(hexValue='ac1413fc'))]
CISCO-CDP-MIB::cdpCacheAddress.10125.9 = 0xac1413fc
How can I convert 0xac14103a
to an IP address?
Or is ist possible to somehow fetch the value of CiscoNetworkAddress
?
Upvotes: 0
Views: 1268
Reputation: 5555
According to CISCO-TC
MIB, you have to interpret the address value by hand taking into account the type of the address as specified by cacheAddressType
column:
CiscoNetworkAddress ::= TEXTUAL-CONVENTION
DESCRIPTION
"Represents a network layer address. The length and format of
the address is protocol dependent as follows:
ip 4 octets
...
ipv6 16 octets
...
http up to 70 octets
SYNTAX OCTET STRING
If it is an IPv4 value, you can convert that octet-string into IPv4 address by hand:
# unpacking your `v` loop variable which is a tuple of SNMP var-bindings
# both `oid` and `value` are pysnmp objects representing SNMP types...
>>> oid, value = v
>>> '.'.join([str(x) for x in value.asNumbers()])
'172.20.16.58'
Or with ipaddress
stdlib module:
>>> ipaddress.IPv4Address(value.asOctets())
IPv4Address('172.20.16.58')
Upvotes: 2