Reputation: 3662
I am using a TextInputLayout with the new function from the Support Library: passwordToggleEnabled. This gives a nice "eye"-icon that lets the user toggle password visibility on and off.
My question is if there is a way to use this functionality but start with password visible?
My xml:
<android.support.design.widget.TextInputLayout
android:id="@+id/password"
android:layout_width="match_parent"
android:layout_height="wrap_content"
app:passwordToggleEnabled="true">
<EditText
android:id="@+id/password_edit"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:hint="@string/prompt_password"
android:inputType="textPassword" />
</android.support.design.widget.TextInputLayout>
The toggle looks similar to this:
I have not found a way to do this in xml, and not a way to manually toggle the visibility after the view is rendered. If I set the input type of the EditText to textVisiblePassword, the toggle is not shown. If I do it in code using for instance mPasswordEditText.setTransformationMethod(null); the password is shown but the toggle is gone and the user can't hide the password again. I know I can do it all manually but just wondering if I can make it work with the new magic toggle
Upvotes: 11
Views: 17600
Reputation: 1
You can add in your xml file in TextInputLayout passwordToggleEnabled="true" passwordToggleDrawable=""@drawable/show_password_selector"
and make your show_password_selector.xml
this will look the same as the picture you sent
Upvotes: 0
Reputation: 2113
Just removing android:inputType="textPassword"
worked for me
Upvotes: 2
Reputation: 363439
With the Material Components Library (1.1.0
, 1.2.0-beta01
, 1.3.0-alpha01
) to start with a visible password just use:
<com.google.android.material.textfield.TextInputLayout
app:endIconMode="password_toggle"
/>
and in your code:
textInputLayout.getEditText().setTransformationMethod(null);
If you want to return to the default behavior:
textInputLayout.getEditText()
.setTransformationMethod(PasswordTransformationMethod.getInstance());
Upvotes: 2
Reputation: 337
To start with Password visible, Do not include
android:inputType="textPassword"
In
<com.google.android.material.textfield.TextInputEditText>
....
</com.google.android.material.textfield.TextInputEditText>
Upvotes: 0
Reputation: 7470
You can use the bellow code:
TextInputLayout yourTextInputLayoutId = findViewById(R.id.yourTextInputLayoutId);
FrameLayout frameLayout = (FrameLayout) (yourTextInputLayoutId).getChildAt(0);
CheckableImageButton checkableImageButton = (CheckableImageButton) frameLayout.getChildAt(1);
checkableImageButton.performClick();
Here yourTextInputLayoutId
is your TextInputLayout id from xml.
Upvotes: 0
Reputation: 204
try this
if (inputEditText.getTransformationMethod() == null) {
inputEditText.setTransformationMethod(new PasswordTransformationMethod());
} else {
inputEditText.setTransformationMethod(null);
}
inputEditText.setSelection(inputEditText.getText().length());
Upvotes: 0
Reputation: 82938
Easiest way is below Another solution is at last of this answer
private void setupPasswordToggleView() {
final TextInputLayout textInputLayout = mRootView.findViewById(R.id.password);
// You can skip post-call and write directly the code which is inside run method.
// But to be safe (as toggle-view is child of TextInputLayout, post call
// has been added.
textInputLayout.post(new Runnable() {
@Override
public void run() {
CheckableImageButton passwordToggleView = textInputLayout.findViewById(R.id.text_input_password_toggle);
// passwordToggleView.toggle(); // Can not use as restricted to use same library group
// passwordToggleView.setChecked(true); // Can not use as restricted to use same library group
passwordToggleView.performClick();
}
});
}
Now let me explain the answer
While looking into code of TextInputLayout.java
I found that, there is a layout design_text_input_password_icon.xml
which is being added to TextInputLayout.java
. Below is that code
private void updatePasswordToggleView() {
if (mEditText == null) {
// If there is no EditText, there is nothing to update
return;
}
if (shouldShowPasswordIcon()) {
if (mPasswordToggleView == null) {
mPasswordToggleView = (CheckableImageButton) LayoutInflater.from(getContext())
.inflate(R.layout.design_text_input_password_icon, mInputFrame, false);
mPasswordToggleView.setImageDrawable(mPasswordToggleDrawable);
mPasswordToggleView.setContentDescription(mPasswordToggleContentDesc);
mInputFrame.addView(mPasswordToggleView); // << HERE IS THAT
.........
}
Now next target was to find design_text_input_password_icon.xml
and lookup id of the toggle view. So found the layout design_text_input_password_icon.xml here and it has written as
18<android.support.design.widget.CheckableImageButton
19 xmlns:android="http://schemas.android.com/apk/res/android"
20 android:id="@+id/text_input_password_toggle"
21 android:layout_width="wrap_content"
22 android:layout_height="wrap_content"
23 android:layout_gravity="center_vertical|end|right"
24 android:background="?attr/selectableItemBackgroundBorderless"
25 android:minHeight="48dp"
26 android:minWidth="48dp"/>
I found the id text_input_password_toggle
of that view and now everything was easy to just find that view in it's viewgroup and perform action on that.
Another solution would be to iterate childs of TextInputLayout
and check if it is CheckableImageButton
and then perform click on it. By this way there would not be dependancy on id of that view and if Android changes the id of view, our solution will still work. (Although they do not change id of a view in normal cases).
private void setupPasswordToggleViewMethod2() {
final TextInputLayout textInputLayout = mRootView.findViewById(R.id.password);
textInputLayout.post(new Runnable() {
@Override
public void run() {
View toggleView = findViewByClassReference(textInputLayout, CheckableImageButton.class);
if (toggleView != null) {
toggleView.performClick();
}
}
});
}
Where findViewByClassReference(View rootView, Class<T> clazz)
original utility class is defined as below
public static <T extends View> T findViewByClassReference(View rootView, Class<T> clazz) {
if(clazz.isInstance(rootView)) {
return clazz.cast(rootView);
}
if(rootView instanceof ViewGroup) {
ViewGroup viewGroup = (ViewGroup) rootView;
for(int i = 0; i < viewGroup.getChildCount(); i++) {
View child = viewGroup.getChildAt(i);
T match = findViewByClassReference(child, clazz);
if(match != null) {
return match;
}
}
}
return null;
}
Upvotes: 5
Reputation: 10910
I was able to get it to start in clear-text mode with the following bit of code. Basically, I had to find the right View using the content description.
If they provided a setter method for mPasswordToggledVisibility
that would make things a lot easier...
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
TextInputLayout til = findViewById(R.id.password);
CharSequence cs = til.getPasswordVisibilityToggleContentDescription();
ArrayList<View> ov = new ArrayList<>();
til.findViewsWithText(ov, cs,View.FIND_VIEWS_WITH_CONTENT_DESCRIPTION);
if( ov.size() == 1 ) {
Checkable c = (Checkable)ov.get(0);
// As far as I can tell the check for "isChecked" here isn't needed,
// since it always starts unchecked by default. However, if you
// wanted to check for state, you could do it this way.
if( c != null && !c.isChecked()) {
ov.get(0).performClick();
}
}
}
Upvotes: 0
Reputation: 42642
One of the ways is, we can search CheckableImageButton
from TextInputLayout
, and then programmatically perform onClick
on it, based on the password visibility status of EditText
.
Here's the code snippet.
private CheckableImageButton findCheckableImageButton(View view) {
if (view instanceof CheckableImageButton) {
return (CheckableImageButton)view;
}
if (view instanceof ViewGroup) {
ViewGroup viewGroup = (ViewGroup) view;
for (int i = 0, ei = viewGroup.getChildCount(); i < ei; i++) {
CheckableImageButton checkableImageButton = findCheckableImageButton(viewGroup.getChildAt(i));
if (checkableImageButton != null) {
return checkableImageButton;
}
}
}
return null;
}
//...
if (passwordEditText.getTransformationMethod() != null) {
CheckableImageButton checkableImageButton = findCheckableImageButton(passwordTextInputLayout);
if (checkableImageButton != null) {
// Make password visible.
checkableImageButton.performClick();
}
}
Upvotes: 0
Reputation: 238
You can use:
yourEditText.setTransformationMethod(new PasswordTransformationMethod());
To re-show the readable password, just pass null as transformation method:
yourEditText.setTransformationMethod(null);
so user can hide it again.
Upvotes: -1