CODEWITHSUNDEEP
pythonpython-3.x
lol
lol

Reputation: 481

Formatting string based on maximum length

longest = len(max(l))
for col1, col2, col3 in zip(l[::3],l[1::3],l[2::3]):
    print('{:^20}|{:^20}|{:^20}'.format(col1,col2,col3))

how can I use longest in place of the 20 so that my formatting will always fit? I also don't want my code looking ugly, so if possible, use formatting or some other way.

Upvotes: 4

Views: 2548

Answers (4)

Jean-François Fabre
Jean-François Fabre

Reputation: 140168

You can pass the width directly in the format:

for cols in zip(l[::3],l[1::3],l[2::3]):
    print('{:^{width}}|{:^{width}}|{:^{width}}'.format(*cols,width=longest))

(adapted from an example quoted in the documentation)

and you don't have to unpack the columns manually. Just unpack them with * in the format call.

Upvotes: 5

Daniel
Daniel

Reputation: 42758

Formats can be nested:

longest = len(max(l))
for col1, col2, col3 in zip(l[::3],l[1::3],l[2::3]):
    print('{:^{len}}|{:^{len}}|{:^{len}}'.format(col1,col2,col3, len=longest))

Upvotes: 3

AKS
AKS

Reputation: 19811

longest = len(max(l))

# tpl will be '{:^20}|{:^20}|{:^20}'
tpl = '{{:^{longest}}}|{{:^{longest}}}|{{:^{longest}}}'.format(longest=longest)
for col1, col2, col3 in zip(l[::3],l[1::3],l[2::3]):
    print(tpl.format(col1,col2,col3))

You can first create the template and then insert the columns.

Double curly braces can be used if you want to literally have the braces in the output:

>>> "{{ {num} }}".format(num=10)
'{ 10 }'

Upvotes: 1

Nick is tired
Nick is tired

Reputation: 7055

Try:

(str(longest).join(['{:^','}|{:^','}|{:^','}']).format(col1,col2,col3))

Upvotes: 1

Related Questions