CODEWITHSUNDEEP
javadate
Code Lღver
Code Lღver

Reputation: 185

java.time.format.DateTimeParseException

I am parsing normal date into LocalDate formate.While converting I am getting One exception called.

Caused by: java.time.format.DateTimeParseException: Text '2017-01-12 00:00:00.0' could not be parsed at index 2 at java.time.format.DateTimeFormatter.parseResolved0(DateTimeFormatter.java:1949) [rt.jar:1.8.0_111] at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1851) [rt.jar:1.8.0_111] at java.time.LocalDate.parse(LocalDate.java:400) [rt.jar:1.8.0_111]

As I know I am getting the same formate.So while converting I am getting this exception.Am I correct. If I am correct How to check the input is the same format or not.

This is my code:-

        DateTimeFormatter DATE_FORMAT =  new DateTimeFormatterBuilder().appendPattern("dd/MM/yyyy").toFormatter();
        LocalDate localDate = LocalDate.parse(myClass.getDate, DATE_FORMAT);
        System.out.println(localDate.format(DATE_FORMAT));

Upvotes: 0

Views: 5413

Answers (2)

Meno Hochschild
Meno Hochschild

Reputation: 44061

The pattern "dd/MM/yyyy" does not match your input. Use the pattern

"uuuu-MM-dd HH:mm:ss.S" instead. And also important: You should not parse such an input to a LocalDate because your input has time information, too. A more edaquate type is LocalDateTime. Full example making a difference between given input (as indicated by your exception) and wished output:

DateTimeFormatter DATE_FORMAT =
    new DateTimeFormatterBuilder().appendPattern("uuuu-MM-dd HH:mm:ss.S").toFormatter();
LocalDateTime ldt = LocalDateTime.parse("2017-01-12 00:00:00.0", DATE_FORMAT);
System.out.println(ldt); // 2017-01-12T00:00

System.out.println(ldt.format(DateTimeFormatter.ofPattern("dd/MM/yyyy"))); // 12/01/2017

Upvotes: 2

ΦXocę 웃 Пepeúpa ツ
ΦXocę 웃 Пepeúpa ツ

Reputation: 48258

this pattern appendPattern("dd/MM/yyyy") can not format this string 2017-01-12 00:00:00.0

use instead appendPattern("yyyy-MM-dd HH:mm.ss.S")

Upvotes: 0

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