Reputation: 171
I want my App to show IncomingCall ViewController, when App Receives Some Incoming Call.
This is my Code that I uses to show Incoming Call.. From my ContactsViewController, which is Active View when Incoming Call take places.
- (void)showIncomigCallVC{
[self performSegueWithIdentifier:@"segueToIncomingCallVC" sender:nil];
}
This is my Code, that is called by Library.
/* Callback called by the library upon receiving incoming call */
static void on_incoming_call(pjsua_acc_id acc_id, pjsua_call_id call_id,
pjsip_rx_data *rdata)
{
pjsua_call_info ci;
PJ_UNUSED_ARG(acc_id);
PJ_UNUSED_ARG(rdata);
pjsua_call_get_info(call_id, &ci);
PJ_LOG(3,(THIS_FILE, "....\n\n\n Incoming call from %.*s!! \n\n\n",
(int)ci.remote_info.slen,
ci.remote_info.ptr));
ContactsViewController *incomingCallVC = [[ContactsViewController alloc]init];
[incomingCallVC showIncomigCallVC];
/* Automatically answer incoming calls with 200/OK */
pjsua_call_answer(call_id, 200, NULL, NULL);
}
And This is my Console Output:
20:39:37.482 XCPjsua.c ......
Incoming call from <sip:[email protected]>!!
2017-01-16 20:39:37.494 simpleVoIP[922:19652] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Receiver (<ContactsViewController: 0x7bea3d00>) has no segue with identifier 'segueToIncomingCallVC''
*** First throw call stack:
(
0 CoreFoundation 0x03a14212 __exceptionPreprocess + 194
1 libobjc.A.dylib 0x034d3e66 objc_exception_throw + 52
2 UIKit 0x01a69893 -[UIViewController shouldPerformSegueWithIdentifier:sender:] + 0
3 simpleVoIP 0x00089ba6 -[ContactsViewController showIncomigCallVC] + 70
4 simpleVoIP 0x00086caf on_incoming_call + 255
5 simpleVoIP 0x000fc273 pjsua_call_on_incoming + 3811
6 simpleVoIP 0x00103294 mod_pjsua_on_rx_request + 84
7 simpleVoIP 0x0012938f pjsip_endpt_process_rx_data + 351
8 simpleVoIP 0x00128bf2 endpt_on_rx_msg + 546
9 simpleVoIP 0x0012fba1 pjsip_tpmgr_receive_packet + 849
10 simpleVoIP 0x001315ec udp_on_read_complete + 316
11 simpleVoIP 0x0014b8e0 ioqueue_dispatch_read_event + 704
12 simpleVoIP 0x0014d5b2 pj_ioqueue_poll + 946
13 simpleVoIP 0x001290c3 pjsip_endpt_handle_events2 + 163
14 simpleVoIP 0x00102023 worker_thread + 99
15 simpleVoIP 0x0014eb96 thread_main + 86
16 libsystem_pthread.dylib 0x04c8a11b _pthread_body + 184
17 libsystem_pthread.dylib 0x04c8a063 _pthread_body + 0
18 libsystem_pthread.dylib 0x04c8993e thread_start + 34
)
libc++abi.dylib: terminating with uncaught exception of type NSException
I am Beginner, any Recommendation will be appreciated.. Thanks in Advance
Upvotes: 2
Views: 127
Reputation: 6151
You are experiencing the crash, because you are programatically allocating your ContactsViewController
, instead of using from the storyboard
.
When you do this:
ContactsViewController *incomingCallVC = [[ContactsViewController alloc]init];
[incomingCallVC showIncomigCallVC];
You are creating an instance of ContactsViewController
, what has nothing to do with the one created in our storyboard
.
It would be possible to overcome on this, however, you are trying to make a segue
call on a viewController
, what has only been loaded to the memory, but is not visible at all. That will never work, it will always crash.
I would recommend to show your viewController
, whatever is behind the segue, straight away, instead of creating a viewController
and show it with a segue.
EDIT:
Using the code below, you should be able to present your desired UIViewController
subclass from the end of your callback function.
// Lets get keywindow
UIWindow* keyWindow = [[[UIApplication sharedApplication] delegate] window];
keyWindow.frame = [UIScreen mainScreen].bounds;
// Lets get `IncomingCallViewController` from storyboard
UIStoryboard *sb = [UIStoryboard storyboardWithName:@"TheNameOfYourStoryboard" bundle:nil];
// do not forget to set the identifier of your viewController on the storyboard as "IncomingCallViewController"
UIViewController *vc = [sb instantiateViewControllerWithIdentifier:@"IncomingCallViewController"];
// Lets present the keyWindow from the main thread
dispatch_async(dispatch_get_main_queue(), ^{
keyWindow.rootViewController = vc;
[keyWindow makeKeyAndVisible];
});
Upvotes: 2