CODEWITHSUNDEEP
phpsymfony
Reza Saadati
Reza Saadati

Reputation: 5419

No existing directory when following use-operator

I have learned that in best case a namespace should represent the path of its file. That means if the file is into the subdirectory "models", like in this case

the namespace should be: namespace vehicles\cars\models;

Now, I have an example from Symfony 3 that looks like this:

use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Route;

I would like to understand where those namespaces are located in. "Symfony" and "Sensio" I can both find in the directory "vendor". For example if I follow the path "Symfony", I don't find "Bundle" or if I follow "Sensio", there is also no folder called "Bundle".

Is that because Symfony doesn't care about the standards or am I just not understanding how it works? I hope it's the second one.

I hope someone can explain that to me, so I can understand.

Upvotes: 0

Views: 47

Answers (1)

Mawcel
Mawcel

Reputation: 2007

Symfony has a more complex file structure the namespace Symfony corresponds to the symfony/symfony/src/Symfony folder so if you are looking for Symfony\Bundle\FrameworkBundle\Controller\Controller just go there and then you will find Bundle/FrameworkBundle.

On the other hand, for most vendor bundles the namespace corresponds to the exact folder structure like for example Sensio\Bundle\FrameworkExtraBundle\Configuration\Route

If you really can't find the path to a vendor bundle you can always try looking into vendor/composer/autoload_namespaces.php and autoload_psr4.php.This is where composer defines the correspondences between directories and namespaces for your project

Hope that helps

Upvotes: 2

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