Reputation: 4317
This is probably an easy question for someone out there to answer. I have a bunch of csv files that I would like to rename using info from within the file.
I have a data frame result
that looks like this:
id year month day precip
0 pod_0001 2017 1 1 2.6
1 pod_0002 2017 1 1 0.4
2 pod_0003 2017 1 1 2.2
3 pod_0004 2017 1 1 25.2
4 pod_0005 2017 1 1 19.4
And I want the name of the file to be YYYY.MM.DD, so in this case it would look like result.2017.01.01.
How do I do that with the to_csv
function like this one..?
result.to_csv("result.csv", na_rep="0")
Upvotes: 1
Views: 361
Reputation: 57085
This solution may be somewhat old-schooled (it uses the %
operator), but it works:
fname = "result.%04d.%02d.%02d.csv" % \
tuple(result[['year','month','day']].drop_duplicates().values[0])
print(fname)
# result.2017.01.01.csv
result.to_csv(fname, na_rep="0")
Upvotes: 1