CODEWITHSUNDEEP
bashmacossed
Vega
Vega

Reputation: 31

Bash - sed, replace line nr 1 in all matched files

I have a directory containing many different folders. In these are some php files. I need to change line nr 1 in all files that match a certain string, in all those folders.

All the files I need to change look something this on line nr 1: <?php some text><?php

I need to replace all those 1st lines with "<?php"

I tried this:

grep -rl something /somedir/folder/ | xargs sed -i '' '1s/.*/<?php/

But it only replaces one of the files in the first folder.

I also tried:

grep -rnw something /somedir/folder/ | xargs sed -i '' '1s/.*/<?php/

But then I get this error:

sed: /somedir/folder//1.php:1:<?php: No such file or directory

Any idea how I can fix this?

Upvotes: 1

Views: 182

Answers (5)

Vega
Vega

Reputation: 31

I found the solution. Now, since I am on OSX, apparently sed does not work exactly the same way as on Linux. Which I did not know. But this is how it can be done:

find ./ -name \*.php -exec sed -i '' -e '1s/.*/<?php/' {} \;

I don't understand exactly why it needs to be like this, but it works.

Upvotes: 0

Vega
Vega

Reputation: 31

grep -rl something /somedir/folder/ | xargs sed -i '' '1s/.*/<\?php/'

This sort of works. But it only changes the file it finds first. And not all files. So basically with this I would have to run it 100 times if I have 100 files =)

Any idea how I can get around that?

Upvotes: 0

dascandy
dascandy

Reputation: 7302

sed -i -e 's/<\?php.*<\?php/<?php/' `find ./ -type f`

To explain:

sed -i

Run, with sed editing in-place

-e 's/

a replacement command, replacing

<\?php.*<\?php

two consecutive php opening statements (escaping the question marks, because this is a regex)

/

with

<?php

one php opening statement

/'

once per line.

`find ./ -type f`

for everything in this folder that's a file.

Upvotes: 2

fancyPants
fancyPants

Reputation: 51938

I don't know what the intention of the empty string was, when executing sed. Without it it works totally fine for me:

grep -rl something /somedir/folder/ | xargs sed -i '1s/.*/<\?php/'

Upvotes: 0

Ipor Sircer
Ipor Sircer

Reputation: 3141

find ./ -iname "*.php" -exec sed '1 s/^<?php some text><?php$/<?php/' -i {} \;

Upvotes: 0

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