CODEWITHSUNDEEP
django
jundymek
jundymek

Reputation: 1043

Django - variables in django templates

Is it possible to write something like this in django templates:

{% for subcategory in category.subcategory.all %}
        <li style="padding-left:20px">
          <a href="/{{category.slug}}/{{subcategory.slug}}">
         {{ subcategory.name }}
         {{ sub_ + str(subcategory) }}
   </a></li>  
{% endfor %} <br>

In my views.py I have:

def index(request):
    context = {}
    categories = Category.objects.select_related()
    subcategories = SubCategory.objects.all()
    context['categories'] = categories
    context['subcategories'] = subcategories
    for subcategory in subcategories:
        sites = Site.objects.filter(subcategory=subcategory, is_active=True)
        print(sites.count())
        context['sub_' + str(subcategory)] = sites.count()
        print(context)
    return render(request, 'mainapp/index.html', context)

I need to count Sites in each subcategory. I thought I can do it by making sub_category1, sub_category2 variables. But I don't know how can I get it in my template. Any ideas? When I write {{ sub_category1 }} it works. I need to put

Upvotes: 1

Views: 92

Answers (1)

RemcoGerlich
RemcoGerlich

Reputation: 31260

{{ sub_ + str(subcategory) }}

No, this isn't going to work.

I would create a method on the SubCategory model:

def get_active_sites(self):
    return Site.objects.filter(subcategory=self, is_active=True)

Now you can use

{{ subcategory.get_active_sites.count }}

in the template. Similarly I'd replace /{{category.slug}}/{{subcategory.slug}} with a method on SubCategory that uses reverse(); probably named get_absolute_url().

Upvotes: 4

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