CODEWITHSUNDEEP
iosswifturlswift3
Robert
Robert

Reputation: 3870

How to encode ''+' character in url string?

I want to encode the + character in my url string, I tried to do that this way:

let urlString = "www.google.com?type=c++"

let result = string.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed)

but this won't work for +.

any idea? Thanks.

Update:

What's more this type= parameter in the url is dynamic, I wouldn't do some implicite replacement on the + character. This type= parameter represents a UITextField value, so there can be typed-in anything.

I'm also curious why addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed) won't work in this particular case?

Upvotes: 6

Views: 3960

Answers (3)

Jonas Deichelmann
Jonas Deichelmann

Reputation: 3743

Swift 5

Using an Extension and add the plus to the not allowed Characters, so you can create your own characterSet and reuse it everywhere you need it. :

extension CharacterSet {
    
    /// Characters valid in part of a URL.
    ///
    /// This set is useful for checking for Unicode characters that need to be percent encoded before performing a validity check on individual URL components.
    static var urlAllowedCharacters: CharacterSet {
        // You can extend any character set you want
        var characters = CharacterSet.urlQueryAllowed
        characters.subtract(CharacterSet(charactersIn: "+"))
        return characters
    }
}

Usage:

let urlString = "www.google.com?type=c++"

let result = urlString.addingPercentEncoding(withAllowedCharacters: .urlAllowedCharacters)

I found a list with the character sets for url encoding. The following are useful (inverted) character sets:

URLFragmentAllowedCharacterSet  "#%<>[\]^`{|}
URLHostAllowedCharacterSet      "#%/<>?@\^`{|}
URLPasswordAllowedCharacterSet  "#%/:<>?@[\]^`{|}
URLPathAllowedCharacterSet      "#%;<>?[\]^`{|}
URLQueryAllowedCharacterSet     "#%<>[\]^`{|}
URLUserAllowedCharacterSet      "#%/:<>?@[\]^`

Source: https://stackoverflow.com/a/24552028/8642838

Upvotes: 4

Viktor Gardart
Viktor Gardart

Reputation: 4490

let allowedCharacterSet = CharacterSet(charactersIn: "!*'();:@&=+$,/?%#[] ").inverted

if let escapedString = "www.google.com?type=c++".addingPercentEncoding(withAllowedCharacters: allowedCharacterSet) {
  print(escapedString)
}

Output:

www.google.com%3Ftype%3Dc%2B%2B

Upvotes: 7

Fawad Masud
Fawad Masud

Reputation: 12344

Replace + with %2B

let urlString = "www.google.com?type=c++"
let newUrlString = aString.replacingOccurrences(of: "+", with: "%2B")

Upvotes: 1

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