CODEWITHSUNDEEP
regex
Stephen O'C
Stephen O'C

Reputation: 77

Square bracket trouble in regex

I'm having trouble with a regex. I basically want to remove everything but brackets, including 0,1,2,3,4,5,6,7,8,9,+,-,*,/

An example would be 

(9*[3*{[(3+3)/5]*7}]) # should give the answer ([{[()]}])

My current regex is

[0123456789+-\\*/] # and it gives the answer ({()]}])

That's giving me the correct answer except [ is matching the regex, and I don't want it too. However ] does not match so I am confused.

Upvotes: 3

Views: 67

Answers (2)

I.G. Pascual
I.G. Pascual

Reputation: 5965

Easiest solution provided by @HamZa in the comments using the negative char ^

[^][(){}]

Another solution is to move the - char to the start or the end of the regex, as in the current position is being treated a range character just like in A-Za-z

[0123456789+\\*/-]

Check it in http://www.regexpal.com/?fam=96675

Upvotes: 3

Bohemian
Bohemian

Reputation: 424993

Use the posix expression for "any non bracket":

[^\p{Ps}\p{Pe}]

and replace it with blank

  • \p{Ps} or \p{Open_Punctuation}: any kind of opening bracket.
  • \p{Pe} or \p{Close_Punctuation}: any kind of closing bracket.

Upvotes: 1

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