CODEWITHSUNDEEP
javascriptsortingbrowser
Saurabh Tiwari
Saurabh Tiwari

Reputation: 5161

Why is the browser sorting in the following way

I have following function:

var sortString = function (a, b) {
            a = a.toLowerCase();
            b = b.toLowerCase();
            if (a < b) return 1;
            if (a > b) return -1;
            return 0;
        }

and I have following two strings:

x = ["B1C3N_EUR_DFAK_ALL_3M_ALL","B1C3N_EUR_BPP_BCO_3M"];

When I run the above function on this array. I expect "B1C3N_EUR_BPP_BCO_3M" to be at index 0 whereas browser returns it in the reverse order. I have checked both on Chrome and IE. Why is it so??

Do I need to replace "-" with some other values. Is there any way I can do it without replacing.

Upvotes: 1

Views: 55

Answers (1)

Nina Scholz
Nina Scholz

Reputation: 386700

You return the wrong value for smaller and greater value in the callback for Array#sort.

if (a < b) return 1;
//                ^  should be -1, because a is smaller than b

if (a > b) return -1;
//                ^^  should be 1, because a is greater than b

For a more concise style, you could use String#localeCompare, which test the given strings and returns a value in the wanted range.

Upvotes: 2

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