Reputation: 31
I got a table with several trs. I want to select 5 trs in a row and give them a background color, then take the next 5 trs and give them another background color - like even and odd, but with 5 elements as a block.
This is what I have tried
var trs = $('table.small-only tr');
for (var i = 1; i < trs.length; i += 5) {
if (i%2 == 0){
// select even blocks
}else {
// select odd blocks
}
}
This doesn't work though.
How can I select blocks containing 5 trs and give the even and odd blocks different background colors in a proper way?
I found a work around:
for (var i = 1; i < trs.length; i += 5) {
trs.slice(i, i + 5).wrapAll("<div></div>");
}
and
div {
&:nth-of-type(odd) {
background: #f2f2f2 !important;
}
}
But clearly putting divs around trs in a table isn't a good way.
Upvotes: 2
Views: 128
Reputation: 106008
You can also use CSS selector :nth-child(xn)
and :not()
:
tr:nth-child(10n - 5)~ tr:not(:nth-child(10n + 1)):not(:nth-child(10n + 2)):not(:nth-child(10n + 3)):not(:nth-child(10n + 4)):not(:nth-child(10n + 5)) {background-color:gray}
tr {
background: turquoise;
counter-increment: trs;
}
tr:nth-child(10n - 5)~ tr:not(:nth-child(10n + 1)):not(:nth-child(10n + 2)):not(:nth-child(10n + 3)):not(:nth-child(10n + 4)):not(:nth-child(10n + 5)) {
background: tomato
}
/* check row numbers */
tr:before {
content: counter(trs);
display: table-cell;
padding: 0.25em;
border: solid;
background: yellow;
}
tr:nth-child(odd):before {
background: gray;
}
td {
padding: 0.25em;
border: solid;
}
<table>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
</table>
Upvotes: 0
Reputation: 381
You can do like that way
HTML
<table class="table">
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
<tr><td>test</td></tr>
</table>
Jquery
$(function(){
var limit = 5;
var arr = ['red','green','yellow','blue','orange'];
$('.table tr').each(function(i,e){
var ind = parseInt((i/limit));
$(this).css('background',arr[ind]);
})
})
Upvotes: 1
Reputation: 64
Here is my example:
function getRandomColor() {
var letters = '0123456789ABCDEF';
var color = '#';
for (var i = 0; i < 6; i++ ) {
color += letters[Math.floor(Math.random() * 16)];
}
return color;
}
var my_table_rows= $('.my-table tr');
var color;
for (var i = 0; i < my_table_rows.length; i++){
if (i % 5 === 0) color = getRandomColor();
my_table_rows.eq(i).css('background', color);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table class="my-table">
<tr><td>1</td></tr>
<tr><td>2</td></tr>
<tr><td>3</td></tr>
<tr><td>4</td></tr>
<tr><td>5</td></tr>
<tr><td>6</td></tr>
<tr><td>7</td></tr>
<tr><td>8</td></tr>
<tr><td>9</td></tr>
<tr><td>10</td></tr>
<tr><td>11</td></tr>
<tr><td>12</td></tr>
<tr><td>13</td></tr>
<tr><td>14</td></tr>
<tr><td>15</td></tr>
<tr><td>16</td></tr>
<tr><td>17</td></tr>
</table>
Upvotes: 4
Reputation: 337626
To achieve this you can loop through the tr
elements in the table stepping over the number of rows you want per group. You can then use slice()
to retrieve the set number of rows before calling addClass()
on them. Try this:
var groupSize = 5;
var classes = ['group1', 'group2'];
var $rows = $("table.small-only tr");
for(var i = 0; i < $rows.length; i += groupSize) {
$rows.slice(i, i + groupSize).addClass(classes[i / groupSize % classes.length]);
}
.group1 { background-color: #C00; }
.group2 { background-color: #0C0; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table class="small-only">
<tr><td>1</td></tr>
<tr><td>2</td></tr>
<tr><td>3</td></tr>
<tr><td>4</td></tr>
<tr><td>5</td></tr>
<tr><td>6</td></tr>
<tr><td>7</td></tr>
<tr><td>8</td></tr>
<tr><td>9</td></tr>
<tr><td>10</td></tr>
<tr><td>11</td></tr>
<tr><td>12</td></tr>
</table>
Upvotes: 2
Reputation: 171689
but clearly putting divs around trs in a table isnt a good way
No, it is invalid html. However you can use <tbody>
instead of <div>
A table can have any number of <tbody>
elements
Upvotes: 1