Get file name from File Path in python

Question

This Question Already have a solution but In my case I'm not getting the correct solution where am I getting wrong?

import os,sys
filename = "C:\Users\Dell\Desktop\ProjectShadow\app2\aapp2s.py"
directory, module_name = os.path.split(filename)
module_name = os.path.splitext(module_name)[0]
print(module_name)
print(directory)

Insterd I want

>> 
aapp2s
C:\User\Dell\Desktop

What's Wrong ?

Answer 1

Try pathlib:

from pathlib import PureWindowsPath
filename = r"C:\Users\Dell\Desktop\ProjectShadow\app2\aapp2s.py"
p = PureWindowsPath(filename)
module_name = p.stem
directory = p.parents[2]
print(module_name)
print(directory)

out:

aapp2s
C:\Users\Dell\Desktop

Answer 2

either use r"C:\Users\Dell\Desktop\ProjectShadow\app2\aapp2s.py" or you can double backshlash the whole thing "C:\\Users\\Dell\\Desktop\\ProjectShadow\\app2\\aapp2s.py"

The strange thing you see on your print is the result of the \a escape char