CODEWITHSUNDEEP
carrayspointers
Awadi Ghassen
Awadi Ghassen

Reputation: 41

C program was not written correctly

I have a little problem in my C application; please help me to reach a solution:

#include <stdio.h>

float t[5];
int i;
float *p;

*p=t;

int main (void)
{

    for (i=0;i<=4;i++)
    {
        printf("t[%d]",i);
        scanf("%f",&t[i]);
    }

    for (i=0;i<=4;i++)
    {
        printf("t[%d]=%f \n",i,*(p+i));
    }

    return 0;
}

When I compile this program the compiler gives me this problem:

[Warning] initialization from incompatible pointer type

What does this mean and how can I modify my code so it compiles and runs correctly?

Upvotes: 0

Views: 64

Answers (3)

user5697768
user5697768

Reputation:

Corrections are commented

#include <stdio.h>

float t[5];
int i;
float *p;

*p=t; //here use p=t as *p will dereference it and t is already a pointer type in this assignment both will mismatch

int main (void)
{

for (i=0;i<=4;i++)
{
    printf("t[%d]",i);
    scanf("%f",&t[i]);
}

for (i=0;i<=4;i++)
{
    printf("t[%d]=%f \n",i,*(p+i));
}

return 0;
}

Upvotes: 0

ΦXocę 웃 Пepe&#250;pa ツ
ΦXocę 웃 Пepe&#250;pa ツ

Reputation: 48268

Doing this 

float t[5];
float *p;
*p=t;

will not compile

error: incompatible types when assigning to type ‘float’ from type ‘float *’

Do instead:

float t[5];
int i;
float* p = t;

Upvotes: 1

Ivaylo Valchev
Ivaylo Valchev

Reputation: 10425

You cannot slap some code outside of a function and hope it executes in some order.

float t[5];

float *p;
*p=t; // illegal, you probably meant p=t; anyway

float *p = t; // fine

int main (void) {}

Upvotes: 6

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