CODEWITHSUNDEEP
c#json
d4ne
d4ne

Reputation: 161

C# get value from deserialized json object

I'm currently Deserializing a json string using the Newtonsoft.Json nuget packet using the following code:

var data = (JObject)JsonConvert.DeserializeObject(json);

Now I'm receiving an object in the following format:

{{  "meta": {    "rap": 2098,    "count": 5  },  "data": [    {      "name": "Gold Tetramino of Mastery",      "rap": 735,      "uaid": "16601901",      "link": "https://www.roblox.com/Gold-Tetramino-of-Mastery-item?id=5786047",      "img": "https://t4.rbxcdn.com/081337d7ea86e6a406512aaa83bbcdeb",      "serial": "---",      "count": 1    },    {      "name": "Silver Tetramino of Accomplishment",      "rap": 385,      "uaid": "16601900",      "link": "https://www.roblox.com/Silver-Tetramino-of-Accomplishment-item?id=5786026",      "img": "https://t1.rbxcdn.com/60da69cd76f8dad979326f63f4a5b657",      "serial": "---",      "count": 1    },    {      "name": "Subzero Ski Specs",      "rap": 370,      "uaid": "155175547",      "link": "https://www.roblox.com/Subzero-Ski-Specs-item?id=19644587",      "img": "https://t4.rbxcdn.com/8ead2b0418ef418c7650d34103d39b6d",      "serial": "---",      "count": 1    },    {      "name": "Rusty Tetramino of Competence",      "rap": 319,      "uaid": "16601899",      "link": "https://www.roblox.com/Rusty-Tetramino-of-Competence-item?id=5785985",      "img": "https://t2.rbxcdn.com/968ad11ee2f4ee0861ae511c419148c8",      "serial": "---",      "count": 1    },    {      "name": "Bluesteel Egg of Genius",      "rap": 289,      "uaid": "16601902",      "link": "https://www.roblox.com/Bluesteel-Egg-of-Genius-item?id=1533893",      "img": "https://t7.rbxcdn.com/48bf59fe531dd1ff155e455367e52e73",      "serial": "---",      "count": 1    }  ]}}

Now I'm trying to get the following value from it:

"rap": 2098,

I just need 2098 and I've been trying the following code:

string rap = data["rap"].Value<string>();

But sadly this wouldn't work. Does anyone have a idea how to get the value?

Upvotes: 16

Views: 48160

Answers (10)

deczaloth
deczaloth

Reputation: 7475

I just came to add Yet another way to get 2098:

After having got your object in the way you actually did:

var data = (JObject)JsonConvert.DeserializeObject(json);

The first you have to note is that the value you want to get is itself a value of the property "meta":

Exact location of the desired value inside the Json object

so, first you have to extract the contents of "meta" by simply calling

data["meta"]

and just then you are able to ask for the Value<string> of "rap":

String rap = data["meta"].Value<string>("rap");

which acctually gives you the value you were looking for:

Console.WriteLine(rap); // 2098

Upvotes: 5

Rian
Rian

Reputation: 21

Use the enumerator to get at the value:

var data = (JObject)JsonConvert.DeserializeObject(json);
var enumerator = data.GetEnumerator();
enumerator.MoveNext();
var dataValue = enumerator.Current.Value.ToString();

Upvotes: 1

Meysam
Meysam

Reputation: 573

the problem is that you are casting the deserialized json into a JObject. if you want to have the JObject then simple do this: 

JObject.Parse(json);

then you have the JObject and you can access a specific path (for extracting value see this )

you have also another option which is to deserialize your json into a class that you have in your code like this: 

var instanceOFTheClass =  JsonConvert.DeserializeObject<YourClassName>(json);

with the above code you can access any property and values you want.

Upvotes: 1

Sri_KMS
Sri_KMS

Reputation: 21

Try to use as following 

var test = JsonConvert.DeserializeObject<dynamic>(param);

var testDTO = new TPRDTO();
testDTO.TPR_ID = test.TPR_ID.Value;

Note: For using of JsonConvert class you have to install Newton-Soft from your package-manager

Upvotes: 2

eocron
eocron

Reputation: 7536

Just use dynamic representation of object:

dynamic obj = JsonConvert.DeserializeObject(json)
var value = obj.meta.rap;

JObject easily convertable to dynamic type itself. You can either get string or int from this value:

var ivalue = (int)obj.meta.rap;
var svalue = (string)obj.meta.rap;

Upvotes: 0

Chris Watts
Chris Watts

Reputation: 891

Instead of declaring as type var and letting the compiler sort it, declare as a dynamic and using the Parse method.

dynamic data = JArray.Parse(json);

Then try 

data.meta.rap

To get the internal rap object. I edited from using the deserializeobject method as i incorrectly thought that had the dynamic return type. See here on json.net documentation for more details: http://www.newtonsoft.com/json/help/html/QueryJsonDynamic.htm

Upvotes: 5

Stuart
Stuart

Reputation: 5496

Try:

var result = data["meta"]["rap"].Value<int>();

or

var result = data.SelectToken("meta.rap").ToString();

or if you don't want to want to pass the whole path in, you could just search for the property like this:

var result = data.Descendants()
                 .OfType<JProperty>()
                 .FirstOrDefault(x => x.Name == "rap")
                 ?.Value;

Upvotes: 7

William
William

Reputation: 2191

string rap = JsonConvert.DeserializeObject<dynamic>(json).meta.rap;
Console.WriteLine(rap); // 2098

If you're not into dynamic (or aren't using .NET 4+), I like how this other answer relies solely on Json.NET's API.

Upvotes: 1

Simon
Simon

Reputation: 2830

The value is actually an int type. Try:

int rap = data["rap"].Value<int>();

Upvotes: 1

Eric
Eric

Reputation: 1847

var jobject = (JObject)JsonConvert.DeserializeObject(json);
var jvalue = (JValue)jobject["meta"]["rap"];
Console.WriteLine(jvalue.Value); // 2098

Upvotes: 3

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