CODEWITHSUNDEEP
python
Telenoobies
Telenoobies

Reputation: 936

Parse only time, and set date to today?

I am trying to convert a time string into a datetime object where the date is today's date. However, I only have a time string and its replace() method does not seem to work.

from datetime import datetime, time,date
timestr = "9:30"
startTime = datetime.strptime(timestr,"%H:%M")
startTime.replace(year=datetime.now().year, month=datetime.now().month, day=datetime.now().day)
print startTime
>>> 1900-01-01 09:30:00

I want:

2017-01-20 09:30:00

Upvotes: 2

Views: 3372

Answers (3)

gold_cy
gold_cy

Reputation: 14216

Here is another solution using another library.

import pendulum
timestr = "9:30"
dt = pendulum.parse(timestr)
<Pendulum [2017-01-20T09:30:00+00:00]>

Or

dt = pendulum.parse(timestr).to_datetime_string()
'2017-01-20 09:30:00'

Upvotes: -1

hansaplast
hansaplast

Reputation: 11573

nicer than replace is combine:

timestr = "9:30"
startTime = datetime.strptime(timestr,"%H:%M")
d = datetime.combine(datetime.today(), startTime.time())

Upvotes: 3

Jean-Fran&#231;ois Fabre
Jean-Fran&#231;ois Fabre

Reputation: 140148

replace doesn't work in-place. Don't ignore the return value, assign it back like this:

startTime = startTime.replace(year=datetime.now().year, month=datetime.now().month, day=datetime.now().day)

and you get:

2017-01-20 09:30:00

Upvotes: 0

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