CODEWITHSUNDEEP
pythonlistlambdamin
Dork
Dork

Reputation: 1886

Elegant way to extract a tuple from list of tuples with minimum value of element

I am having list of tuple from which I want the tuple with the minimum value at index 1. For example, if my list is like:

a =[('a', 2), ('ee', 3), ('mm', 4), ('x', 1)]

I want the returned tuple to be ('x', 1).

Currently I am using sorted function to get this result like:

min=sorted(a, key=lambda t: t[1])[0]

Is there better ways to do it? Maybe with min function?

Upvotes: 4

Views: 989

Answers (2)

Moinuddin Quadri
Moinuddin Quadri

Reputation: 48090

You may use min() function with key parameter in order to find the tuple with minimum value in the list. There is no need to sort the list. Hence, your min call should be like:

>>> min(a, key=lambda t: t[1])
('x', 1)

Even better to use operator.itemgetter() instead of lambda expression; as itemgetter are comparatively faster. In this case, the call to min function should be like:

>>> from operator import itemgetter

>>> min(a, key=itemgetter(1))
('x', 1)

Note: min() is a in-built function in Python. You should not be using it as a variable name.

Upvotes: 8

Sandipan Dey
Sandipan Dey

Reputation: 23109

This will also work:

min([x[::-1] for x in a])[::-1]
# ('x', 1)

Upvotes: 1

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