Reputation: 29
just a simple question. How can I show 1 specific error from this?
$search_query = mysql_query("SELECT * FROM users WHERE username = '$username' OR email = '$email'");
$num_row = mysql_num_rows($search_query);
if($num_row >= 1){
$errors['username'] = "username is unavailable.";
$errors['email'] = "Email address is unavailable.";
}else
{//insert.....
They both show the error, but not working with $username
.
Just can't figure it out.
And if it's not asking too much, can you please add if the username/email is available?
Thanks in advance.
I'll put the $errors
after the input tag:
<p>username:</p>
<input type="text" name="username" id="username" value="<?php if(isset($_POST['username'])){echo $_POST['username'];} ?>">
<?php if(isset($errors['username'])){echo "<h5>" .$errors['username']. "</h5>"; } ?></td>
</tr>
<td><p>email:</p>
<input type="text" name="email" id="email" value="<?php if(isset($_POST['email'])){echo $_POST['email'];} ?>">
<?php if(isset($errors['email'])){echo "<h5>" .$errors['email']. "</h5>"; } ?></td>
</tr>
Upvotes: 0
Views: 41
Reputation: 340
mysql_query() or die(mysql_error());
like
$search_query = mysql_query("SELECT * FROM users WHERE username = '$username' OR email = '$email'") or die(mysql_error());
And
$num_row = mysql_num_rows($search_query)or die(mysql_error());
Upvotes: 3