CODEWITHSUNDEEP
pythonjsondictionary
alphanumeric
alphanumeric

Reputation: 19379

How can I convert nested dictionary keys to strings?

original dictionary keys are all integers. How can I convert all the integer keys to strings using a shorter approach?

original = {1:{},2:{101:"OneZeroOne",202:"TwoZeroTwo"}}

result = {}
for key in original:
    if not key in result:
        result[str(key)]={}
    for i, value in original[key].items():
        result[str(key)][str(i)] = value
print result

prints:

{'1': {}, '2': {'202': 'TwoZeroTwo', '101': 'OneZeroOne'}}

Upvotes: 5

Views: 2253

Answers (4)

Stephen Rauch
Stephen Rauch

Reputation: 49842

Depending on what types of data you have:

original = {1:{},2:{101:"OneZeroOne",202:"TwoZeroTwo"}}
result= json.loads(json.dumps(original))
print(result)

prints:

{'2': {'101': 'OneZeroOne', '202': 'TwoZeroTwo'}, '1': {}}

Upvotes: 3

宏杰李
宏杰李

Reputation: 12168

import json
original = {1:{},2:{101:"OneZeroOne",202:"TwoZeroTwo"}}
text = json.dumps(original)
json.loads(text)

out:

{'1': {}, '2': {'101': 'OneZeroOne', '202': 'TwoZeroTwo'}}

Upvotes: 3

wwii
wwii

Reputation: 23783

def f(d):
    new = {}
    for k,v in d.items():
        if isinstance(v, dict):
            v = f(v)
        new[str(k)] = v
    return new

Upvotes: 3

thebjorn
thebjorn

Reputation: 27361

If you don't know the number of levels, then a recursive solution is probably best:

def convert_dict(d):
    return {str(k): convert_value(v) for k,v in d.items()}

def convert_list(lst):
    return [convert_value(item) for item in lst]

def convert_value(v):
    if isinstance(v, dict):
        return convert_dict(v)
    elif isinstance(v, list):
        return convert_list(v)
    # more elifs..
    else:
        return v

if you know that all values are either dicts or simple values, then you can remove all the elifs and the convert_list function

Upvotes: 2

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