CODEWITHSUNDEEP
pythoncharfilenames
urgeo
urgeo

Reputation: 641

access a file with not fully known filename in python

I have a huge database of files whose names are like:

XYZ-ABC-K09235D1-20151220-5H1E2H4A.txt
XYZ-ABC-W8D2S5G5-20151225-HG2EK4GE.txt
XYZ-ABC-ME2C5K32-20160206-DD8BA4R6.txt
etc...

Names have all the same structure:

'XYZ-ABC-' + 8 random char + '%y%m%d' + 8 random char + '.txt'

Now, I need to open a file, given the date. The point is that, I don't know the exact name of the file, as there are some random chars within. For instance, for datetime 12/05/2014 I know the filename will be something like

XYZ-ABC-????????-20140512-????????.txt

but I don't know the exact name when using f.open command. What could be the best way to do this? (I thought about first creating a list with all filenames, but I don't know whether it's a good technique or if it's better to use something like glob...). Thank you in advance.

Upvotes: 1

Views: 159

Answers (1)

Jay Parikh
Jay Parikh

Reputation: 2489

You can use following code

import os fileName = [filename for filename in os.listdir('.') if filename.startswith("prefix") and 'otherstring' in filename]

Hope this helps !

Upvotes: 2

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