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pythonpython-3.xformatstring-formatting
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Reputation: 667

How to set variable precision for new python format option

I am loving the new format option for strings containing variables, but I would like to have a variable that sets the precision through out my script and I am not sure how to do that. Let me give a small example:

a = 1.23456789
out_str = 'a = {0:.3f}'.format(a)
print(out_str)

Now this is what I would want to do in pseudo code:

a = 1.23456789
some_precision = 5
out_str = 'a = {0:.(some_precision)f}'.format(a)
print(out_str)

but I am not sure, if it is possibly and if it is possibly how the syntax would look like.

Upvotes: 5

Views: 2512

Answers (2)

Martijn Pieters
Martijn Pieters

Reputation: 1123440

You can nest placeholders, where the nested placeholders can be used anywhere in the format specification:

out_str = 'a = {0:.{some_precision}f}'.format(a, some_precision=some_precision)

I used a named placeholder there, but you could use numbered slots too:

out_str = 'a = {0:.{1}f}'.format(a, some_precision)

Autonumbering for nested slots (Python 2.7 and up) is supported too; numbering still takes place from left to right:

out_str = 'a = {0:.{}f}'.format(a, some_precision)

Nested slots are filled first; the current implementation allows you to nest placeholders up to 2 levels, so using placeholders in placeholders in placeholders doesn't work:

>>> '{:.{}f}'.format(1.234, 2)
'1.23'
>>> '{:.{:{}}f}'.format(1.234, 2, 'd')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: Max string recursion exceeded

You also can't use placeholders in the field name (so no dynamic allocation of values to slots).

Upvotes: 16

Mohammad Yusuf
Mohammad Yusuf

Reputation: 17074

Or you can use numbering.

a = 1.23456789
some_precision = 5
out_str = 'a = {0:.{1}f}'.format(a,some_precision)
print(out_str)

Ouptut:

a = 1.23457

Upvotes: 2

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