CODEWITHSUNDEEP
phpgd
moonwalker
moonwalker

Reputation: 485

Can't find image in GD (PHP)

I'm trying to put a watermark on my images, but the script can't find my watermark image. I'm doing this dynamically, so for each user there is a watermark in the watermarks folder. When trying to use this code:

session_start();
$username = $_SESSION['_user_login'];

// Set the path to the image to watermark
$input_image = $targetPath.$newName; 
// Read in the text watermark image
$watermark = imagecreatefrompng("../watermarks/$username.png");

Nothing happens. I tried printing the user name variable and it works fine. I even tried to just print the image and it works also. But when using imagecreatefrompng, the watermark image is never found. Looking in my log I see the following error:

Warning: imagecreatefrompng(../watermarks/.png) [function.imagecreatefrompng]: failed to open stream: No such file or directory

I don't get it. What am I doing wrong?

Thanks.

Upvotes: 0

Views: 839

Answers (6)

moonwalker
moonwalker

Reputation: 485

Tried everything but for some reason the SESSION variable just doesn't work in the imagecreatefrompng function.

To solve this I just post the username as a hidden variable. This seems to work fine for the moment.

Thanks everyone for the help. It's appreciated.

mw

Upvotes: 0

Nathan Hess
Nathan Hess

Reputation: 731

Well the $username variable is blank according to that error. Do a var_dump($_SESSION) in your script to double check your are properly storing the _user_login variable.

Also I would suggest using curly braces when putting variables in strings.

$watermark = imagecratefrompng("../watermarks/{$username}.png");

This will make it easy to see your variables and prevent php from using the wrong variable name.

Upvotes: 0

Powerlord
Powerlord

Reputation: 88836

.. is resolved from PHP's current working directory. Presumably, this is the directory that the PHP file is currently in.

Generally, it's a better idea to resolve directories from $_SERVER['DOCUMENT_ROOT'] so that they are absolute* directories rather than relying on nothing doing a chdir before your file is opened.

$watermark = imagecreatefrompng($_SERVER['DOCUMENT_ROOT'] . "/watermarks/$username.png");

*For a given definition of absolute.

Upvotes: 0

jocull
jocull

Reputation: 21175

$username appears to be blank. Hence, "imagecreatefrompng(../watermarks/.png)"

I'd suggest debugging starting with making sure the file path you're requesting is valid.

session_start();
$username = $_SESSION['_user_login'];

// Set the path to the image to watermark
$input_image = $targetPath.$newName; 
// Read in the text watermark image
$filestring = "../watermarks/$username.png";
echo "LOOKING FOR $filestring";
$watermark = imagecreatefrompng($filestring);

Upvotes: 0

Skilldrick
Skilldrick

Reputation: 70879

The clue's in the warning:

imagecreatefrompng(../watermarks/.png)

It's looking for a file called .png, so obviously your $username = $_SESSION['_user_login']; isn't actually returning the username, or the string isn't getting created properly.

Have you tried using braces in the string like this: "../watermarks/{$username}.png"? If that doesn't work then you've got a problem with your username.

Upvotes: 1

Evan Mulawski
Evan Mulawski

Reputation: 55354

You would need to use:

$watermark = imagecreatefrompng(dirname(dirname(__FILE__)) . "/watermarks/" . $username . ".png");

(You can print dirname(__FILE__) to check your directory structure before using this method).

Upvotes: 1

Related Questions