Reputation: 399
There are two lines "LongLine" and "ShortLine".
<svg width="120" height="120" viewBox="0 0 120 120" xmlns="http://www.w3.org/2000/svg">
<line id="LongLine" x1="20" y1="350" x2="350" y2="50" stroke-width="2" stroke="black"/>
<line id="ShortLine" x1="20" y1="350" x2="0" y2="0" stroke="#ff00ff" stroke-width="10" />
</svg>
<svg width="120" height="120" viewBox="0 0 120 120" xmlns="http://www.w3.org/2000/svg">
<line id="LongLine" x1="20" y1="350" x2="350" y2="50" stroke-width="2" stroke="black"/>
<line id="ShortLine" x1="20" y1="350" x2="185" y2="200" stroke="#ff00ff" stroke-width="10" />
</svg>
In other words x1, y1, x2, y2 of "LongLine", and x1, y1 of "ShortLine" are known.
Wanted are the x2, y2 of "ShortLine", but so that the angle of both lines remains the same.
Here is my wrong approach:https://jsfiddle.net/rmLdm15z/8/
Thanks in advance.
Upvotes: 4
Views: 4924
Reputation: 1421
One way is to calculate the unit vector u
given by the points (x1, y1)
and (x2, y2)
of the "LongLine", then add it to (x1, y1)
multiplied by the desired size of the "ShortLine", call it short_d
.
const dx = x2 - x1
const dy = y2 - y1
const d = Math.sqrt(dx * dx + dy * dy)
const ux = dx / d
const uy = dy / d
const shortLine = document.getElementById('ShortLine')
shortLine.setAttribute('x1', `${x1}`)
shortLine.setAttribute('y1', `${y1}`)
shortLine.setAttribute('x2', `${x1 + short_d * ux}`)
shortLine.setAttribute('y2', `${y1 + short_d * uy}`)
Take a look on Vector algebra.
Upvotes: 1
Reputation: 257
Try this:
var shortLine = document.getElementById('ShortLine')
shortLine.y1.baseVal.value = 500
console.log(shortLine)
// Gives us:
// <line id="ShortLine" x1="20" y1="500" x2="185" y2="200" stroke="#ff00ff" stroke-width="10"></line>
As a general guideline, you can always view all the properties an object gives you through the console. For example, console.log(shortLine.y1)
is how you find that you can set baseVal.value
.
Upvotes: 6