CODEWITHSUNDEEP
cfor-loop
Syed Hasan
Syed Hasan

Reputation: 57

Display numbers an odd number of times in C

An output is given in the following form :

OUTPUT :
0
111
22222
3333333
... up to 9.

The task I was given was to write a code for this output using nested for loops.

The closest I have gotten to figuring it out is this:

#include <stdio.h>
#include <conio.h>

int main()
{
    int x=0, y=0, z=0;

    for (x=1; x<=9; x=x+1)
    {
        printf("\n");
        for (y=0; y<=10; y=y+1)
        {
            for(z==y; y<x; y++)
            {
                printf("%d", x);    
            }
        }
    }
}

I was also instructed to "Refrain from using Arrays or others methods of solving this question."

I cant figure out my mistake. Help would be appreciated.

The output from this program is here: https://i.sstatic.net/IfNPe.png

Upvotes: 1

Views: 127

Answers (2)

Uriel
Uriel

Reputation: 16184

Iterate all numbers (x), while incrementing the number of prints (y) by 2, strting from 1 (see online):

for (int x = 0, y = 1; x <= 9; x++, y += 2)
{
    for (int z = 0; z < y; z++)
            printf("%d", x);        
    printf("\n");
}

I would say 

for (int x = 0; x <= 9; x++) {
        for (int y = 0; y < x * 2 + 1; y++)
                printf("%d", x);
        printf("\n")
}

is more elegant, but it can be a little tricky to follow.

Upvotes: 4

Paul Ogilvie
Paul Ogilvie

Reputation: 25286

That would be then:

int main()
{
    int x, y, z;

    printf("0");
    for (x=1, y=3; x<=9; x++, y+=2)
    {
        printf("\n");
        for (z=y; z; z--)
        {
            printf("%d", x);    
        }       
    }
}

Output:

0
111
22222
3333333
444444444
55555555555
6666666666666
777777777777777
88888888888888888
9999999999999999999

Upvotes: 1

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