Reputation: 11275
If I build a Swift dictionary, i.e. [String: Any]
how can I return that as JSON? I tried this, but it gives me the error: Argument labels '(node:)' do not match any available overloads
.
drop.get("test") { request in
var data: [String: Any] = [:]
data["name"] = "David"
data["state"] = "CA"
return try JSON(node: data)
}
Upvotes: 3
Views: 1614
Reputation: 26177
Convoluted as heck, but this allows you to use [String:Any].makeNode(), as long as the internals are NodeRepresentable, NSNumber based, or NSNull :) --
import Node
enum NodeConversionError : LocalizedError {
case invalidValue(String,Any)
var errorDescription: String? {
switch self {
case .invalidValue(let key, let value): return "Value for \(key) is not NodeRepresentable - " + String(describing: type(of: value))
}
}
}
extension NSNumber : NodeRepresentable {
public func makeNode(context: Context = EmptyNode) throws -> Node {
return Node.number(.double(Double(self)))
}
}
extension NSString : NodeRepresentable {
public func makeNode(context: Context = EmptyNode) throws -> Node {
return Node.string(String(self))
}
}
extension KeyAccessible where Key == String, Value == Any {
public func makeNode(context: Context = EmptyNode) throws -> Node {
var mutable: [String : Node] = [:]
try allItems.forEach { key, value in
if let _ = value as? NSNull {
mutable[key] = Node.null
} else {
guard let nodeable = value as? NodeRepresentable else { throw NodeConversionError.invalidValue(key, value) }
mutable[key] = try nodeable.makeNode()
}
}
return .object(mutable)
}
public func converted<T: NodeInitializable>(to type: T.Type = T.self) throws -> T {
return try makeNode().converted()
}
}
With that header you can:
return try JSON(node: data.makeNode())
Upvotes: 2
Reputation: 939
JSON cannot be initialized from a [String : Any]
dictionary because Any
is not convertible to Node
.
There are only a limited number of types that Node can be. (See Node source). If you know your objects are all going to be the same type, use a dictionary that only allows that type. So for your example, [String : String]
.
If you're going to be getting data from the request, you can try using request.json
as is used in the documentation here.
Another (possibly better) solution would be to make your dictionary [String: Node]
and then you can include any type that conforms to Node
. You may have to call the object's makeNode()
function to add it to the dictionary though.
Upvotes: 1