CODEWITHSUNDEEP
javaclassobjectarraylist
HPotter
HPotter

Reputation: 141

Creating a class that stores all objects created in an ArrayList?

So I created three class called "Address", "Job" and "Person" with "Person" being my primary class. I test these by:

Address person2Address = new Address(1054, "Pico St", "Los Angeles", "CA", "97556");
    Address person2JobAddress = new Address(5435, "James St", "New York", "NY", "56565");
    ArrayList<String> person2Phone = new ArrayList<String>();
    person2Phone.add("555-555-55");
    Job person2Job = new Job("Mechanic", 35000.00, person2JobAddress);
    Person person2 = new Person("Rollan Tico", "New York", 'M', person2Address, person2Job, person2Phone);
    System.out.println(person2.toString());

They print everything correctly. Now, this is where I am stuck. How would I create a different class called Persons that stores each Person created in a ArrayList? Would there be any constrcunert? I know that an Arrayist is created by ArrayList<Person> List = new ArrayList<Person>();, but got a feeling I am missing something.

Upvotes: 0

Views: 802

Answers (2)

Mustafa sabir
Mustafa sabir

Reputation: 4360

If you create a class for an object like Person, you don't need to create a Persons class just to store multiple Person objects. Unless you have to define operations which involves multiple Person Objects, like for example a Group class with operations performed on group pf persons, in which case creating a Persons or Group class makes sense. In your case I would assume you just need to store multiple Person objects and for that ArrayList<Person> will suffice.

ArrayList<Person> persons = new ArrayList<Person>();
persons.add(new Person(.....)); //add Person
.
.
Person person1=persons.get(1); //get Person by index

Upvotes: 0

harivis
harivis

Reputation: 82

You can have Collection like

Collection<Person> persons = new ArrayList<Person>(); persons.add(person2);

Or in some case, like JSON serialization you cannot seralize a list as the root element. so,

import java.util.*

public class Persons {

  private Collection<Person> persons;

  //If you want the clients to have flexibility to choose the implementation of persons collection.
  //Else, hide this constructor and create the persons collection in this class only.
  public Persons(Collection<Person> persons) {
    this.persons = persons;
  }

  public void addPerson(Person person) {
   persons.add(person);
  }
}

Upvotes: 1

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