CODEWITHSUNDEEP
kotlin
Kenji Tomita
Kenji Tomita

Reputation: 35

Int::class.javaPrimitiveType.kotlin reference not equal to Int::class.javaObjectType.kotlin

I think that CASE 2 should also return true. Is this behavior correct?

// CASE 1
Int::class.javaPrimitiveType!!.kotlin == Int::class.javaObjectType.kotlin // true

// CASE 2
Int::class.javaPrimitiveType!!.kotlin === Int::class.javaObjectType.kotlin // false

Upvotes: 1

Views: 542

Answers (2)

Alexander Udalov
Alexander Udalov

Reputation: 32776

This behavior is correct. KClass instances for a primitive type and the corresponding object type are equal (==), however they're created from different java.lang.Class instances and since .java always returns the original Class instance the KClass was constructed from, it wouldn't be possible for them to also be identical (===).

Upvotes: 7

Bombe
Bombe

Reputation: 83852

Short answer: yes.

Long answer: of course it’s hard to tell what the intended behaviour should be as nobody of us was involved in making that decision, or writing that code. However, I don’t think that it’s really a requirement that these two objects are in fact the same object; equality is sufficient, reference equality is not required here.

Upvotes: 0

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