CODEWITHSUNDEEP
linuxgrep
haru
haru

Reputation: 325

Grep with multiple keywords and output multiple lines

I want to grep lines contains all 3 different patterns, and output them with 2 previous lines and 1 next line.

This is the command I could grep without multiple line output. Now I want to add 3 additional line mentioned above. Can I put -A and -B together? Or do I have to use -C? Where should I put those options, all in three conditions or first or last?

grep -e Melon -e Banana -e Lemon *txt | grep Tomato | grep Milk

This is sample input

Egg Tomato    
Salad Coffee
Melon Tomato Milk
Noodle Salmon
Banana Potato Milk
Salmon Rice

Expected output is

Egg Tomato 
Salad Coffee
Melon Tomato Milk
Noodle Salmon

Upvotes: 1

Views: 979

Answers (1)

Jose Ricardo Bustos M.
Jose Ricardo Bustos M.

Reputation: 8174

A large solution, you want: Two lines above and one line below of pattern: (Melon or Banana or Lemon) and Tomato and Milk

grep -A1 -B2 -E -e "(Tomato.*Milk|Milk.*Tomato).*(Melon|Banana|Lemon)" \
                -e "(Melon|Banana|Lemon).*(Tomato.*Milk|Milk.*Tomato)" \
                -e "Tomato.*(Melon|Banana|Lemon).*Milk" \
                -e "Milk.*(Melon|Banana|Lemon).*Tomato" *txt

Only for fun

Another solution using awk

awk '
    flag{print; flag=0}
    /Melon|Banana|Lemon/ && /Milk/ && /Tomato/{
        printf "%s\n%s\n%s\n",prev[0],prev[1],$0
        flag=1; next
    }
    {prev[0]=prev[1]; prev[1]=$0}' *txt

Upvotes: 2

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