CODEWITHSUNDEEP
pythonbashterminal
Paktros
Paktros

Reputation: 72

How to call a python script on a new shell window from python code?

I'm trying to execute 10 python scripts from python code and open each of them in a new shell window.

My code :

for i in range(10):
    name_of_file = "myscript"+str(i)+".py"
    cmd = "python " + name_of_file
    os.system("gnome-terminal -e 'bash -c " + cmd + "'")

But each script file are not executing, I get only the live interpreter of python in the new terminal...

Thank you guys

Upvotes: 0

Views: 2289

Answers (2)

fedepad
fedepad

Reputation: 4609

I would suggest using the subprocess module (https://docs.python.org/2/library/subprocess.html).
In this way, you'll write something like the following:

import subprocess

cmd = ['gnome-terminal', '-x', 'bash', '-c']
for i in range(10):
    name_of_file = "myscript"+str(i)+".py"
    your_proc = subprocess.Popen(cmd + ['python %s' % (name_of_file)])
    # or if you want to use the "modern" way of formatting string you can write
    # your_proc = subprocess.Popen(cmd + ['python {}'.format(name_of_file)])
    ...

and you have more control over the processes you start.
If you want to keep using os.system(), build your command string first, then pass it to the function. In your case would be:

cmd = 'gnome-terminal -x bash -c "python {}"'.format(name_of_file)
os.system(cmd)

something along these lines.
Thanks to @anishsane for some suggestions!

Upvotes: 1

Hippy Surfer
Hippy Surfer

Reputation: 21

I think that it is to do with the string quoting of the argument to os.system. Try this:

os.system("""gnome-terminal -e 'bash -c "{}"'""".format(cmd))

Upvotes: 1

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