Reputation: 31
For my class I need to create a function that takes in multiple parameters at runtime:
void main(int x, int y, int generation, char *layout[20])
However when the program runs with my input for these variables the information is not stored and in the debugging process
run 3 3 3 Test_Round
print x // returns 5
print y // returns -8779
How do I pass multiple arguments into the main function so main will recognize the parameters I give it?
Thanks everyone! I just used argv[1] and so on to get the proper data I need!
Upvotes: 2
Views: 13339
Reputation: 6421
The standard is clear about how you need to declare your main function.
From the C99 Standard:
5.1.2.2.1 Program startup
The function called at program startup is named main. The implementation declares no prototype for this function. It shall be defined with a return type of int and with no parameters:
int main(void) { /* ... */ }
or with two parameters
(referred to here as
argc
andargv
, though any names may be used, as they are local to the function in which they are declared):
int main(int argc, char *argv[]) { /* ... */ }
or equivalent;9) or in some other implementation-defined manner.
If they are declared, the parameters to the main function shall obey the following constraints:
— The value of
argc
shall be nonnegative.—
argv[argc]
shall be a null pointer.— If the value of
argc
is greater than zero, the array membersargv[0]
throughargv[argc-1]
inclusive shall contain pointers to strings, which are given implementation-defined values by the host environment prior to program startup. The intent is to supply to the program information determined prior to program startup from elsewhere in the hosted environment. If the host environment is not capable of supplying strings with letters in both uppercase and lowercase, the implementation shall ensure that the strings are received in lowercase.— If the value of
argc
is greater than zero, the string pointed to byargv[0]
represents the program name;argv[0][0]
shall be the null character if the program name is not available from the host environment. If the value of argc is greater than one, the strings pointed to byargv[1]
throughargv[argc-1]
represent the program parameters.— The parameters
argc
andargv
and the strings pointed to by theargv
array shall be modifiable by the program, and retain their last-stored values between program startup and program termination.
Upvotes: 6
Reputation: 34568
You can not pass more than two argument in main function. In main function, you can pass only two
argument or Zero
argument.
Using following parameters, you can pass the value command line.
int main(int argc, char *argv[])
Upvotes: 0
Reputation: 134286
void main(int x, int y, int generation, char *layout[20])
is an invalid signature of main()
. You need to use
int main(int argc, char *argv[])
where, argv[0]
to argv[argc-1]
will hold the parameters passed to main()
.
Quoting C11
, chapter §5.1.2.2.2,
If the value of
argc
is greater than zero, the string pointed to byargv[0]
represents the program name;argv[0][0]
shall be the null character if the program name is not available from the host environment. If the value ofargc
is greater than one, the strings pointed to byargv[1]
throughargv[argc-1]
represent the program parameters.
Upvotes: 1