Reputation: 17631
I've installed sqlite3
from source on Linux and placed this into the subdirectory of C code with a Makefile. This is what the Makefile
looks like
CC = gcc
CFLAGS = -Wall -g -std=c99
SOURCES := src/file1.c src/file2.c src/file3.c
LIB := -lm -lsqlite3
INC := -I include -I path/to/pathname/sqlite3/include
all:
@mkdir -p bin/
$(CC) $(CFLAGS) $(SOURCES) main.c -L path/to/pathname/sqlite3/ -o bin/software $(LIB) $(INC)
clean:
rm -f bin/sofware
However, whenever I try executing make
, I get this error:
gcc -Wall -g -std=c99 src/file1.c src/file2.c src/file3.c -I include -I path/to/pathname/sqlite3/include
/usr/bin/ld: cannot find -lsqlite3
collect2: error: ld returned 1 exit status
make: *** [all] Error 1
I don't understand. sqlite3
is in path/to/pathname/sqlite3/
Here is the list of files/executables in path/to/pathname/sqlite3/
:
aclocal.m4 config.log configure.ac install-sh ltmain.sh missing shell.o sqlite3.h sqlite3.pc.in
autom4te.cache config.status depcomp lib Makefile README sqlite3 sqlite3.lo tea
bin config.sub include libsqlite3.la Makefile.am share sqlite3.c sqlite3.o
config.guess configure INSTALL libtool Makefile.in shell.c sqlite3ext.h sqlite3.pc
How does one properly allow this C code to compile properly with access to sqlite3?
Upvotes: 0
Views: 2710