CODEWITHSUNDEEP
julia
Colin T Bowers
Colin T Bowers

Reputation: 18580

How to convert any type into String in Julia

Using Julia, I'd like to reliably convert any type into type String. There seems to be two ways to do the conversion in v0.5, either the string function or String constructor. The problem is that you need to choose the right one depending upon the input type.

For example, typeof(string(1)) evaluates to String, but String(1) throws an error. On the other hand, typeof(string(SubString{String}("a"))) evaluates to Substring{String}, which is not a subtype of String. We instead need to do String(SubString{String}("a")).

So it seems the only reliable way to convert any input x to type String is via the construct:

String(string(x))

which feels a bit cumbersome.

Am I missing something here?

Upvotes: 14

Views: 6701

Answers (1)

Fengyang Wang
Fengyang Wang

Reputation: 12051

You should rarely need to explicitly convert to String. Note that even if your type definitions have String fields, or if your arrays have concrete element type String, you can still rely on implicit conversion.

For instance, here are examples of implicit conversion:

type TestType
    field::String
end

obj = TestType(split("x y")[1])  # construct TestType with a SubString
obj.field  # the String "x"

obj.field = SubString("Hello", 1, 3)  # assign a SubString
obj.field  # the String "Hel"

Upvotes: 6

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