CODEWITHSUNDEEP
regexssi
andi
andi

Reputation: 6522

How to get SSI variable REQUEST_URI without query parameters

I'm trying to get the pathname part of the REQUEST_URI, without the query parameters. I need to do this in raw SSI, without any PHP or anything.

If I do something like <!--#echo var="REQUEST_URI" -->, that will output the pathname plus the query parameters, so if the browser URL shows http://example.com/foo.html?bar, that would return /foo.html?bar. But I need to return only /foo.html. Is there a way to do that directly inside an echo statement?

Note: It needs to use the requested uri only. The actual file paths on the server are very different and I cannot display those.

Upvotes: 2

Views: 2040

Answers (3)

jcde_1974
jcde_1974

Reputation: 11

This code works for me :

<!--#if expr="$REQUEST_URI = /([^?]+)\?.*/" -->
    <!--#set var="URL_WITHOUT_QUERY_STRING" value="$1" -->
    <!--#echo var='URL_WITHOUT_QUERY_STRING' -->
<!--#endif -->

Upvotes: 1

mofoe
mofoe

Reputation: 3804

I don't have a running nginx with SSI around, so i am just guessing here. But maybe you can try to use a regular expression to extract what you want. Maybe something like this: 

<!--# if expr="$REQUEST_URI = /(.+)\?.*/" -->
    <!--# echo var="1" -->
<!--# endif -->

I am not sure about the \ before the ?.

Upvotes: 3

mofoe
mofoe

Reputation: 3804

You could try to use the DOCUMENT_URI variable instead:

<!--#echo var="DOCUMENT_URI" -->

SCRIPT_NAME seems to work too:

<!--#echo var="SCRIPT_NAME" -->

Upvotes: 2

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