CODEWITHSUNDEEP
pythonuuid
michaelcoyote
michaelcoyote

Reputation: 161

UUID check using python UUID module changes UUID

I've run into this odd behaviour when I use the UUID() function from the python uuid module to check one of our test uuids.

from uuid import UUID uuid1 = UUID('00000000-0000-0000-0000-000000000000', version=1) print uuid1 00000000-0000-1000-8000-000000000000

without the version it works as expected uuid0 = UUID('00000000-0000-0000-0000-000000000000') print uuid0 00000000-0000-0000-0000-000000000000

Is this expected behavour? Are there any other side effects that I need to worry about?

Is there a safer or better way to test uuids in python I should use instead of the UUID() function or am I misusing this function?

Upvotes: 3

Views: 806

Answers (1)

iklinac
iklinac

Reputation: 15758

From code comment

 The 'version' argument is optional; if given, the resulting
        UUID will have its variant and version set according to RFC 4122,
        overriding the given 'hex', 'bytes', 'bytes_le', 'fields', or 'int'.

RFC versions

To generate uuid you can use one of following functions depending on uuid type

uuid1(), uuid3(), uuid4(), uuid5()

And as you already know UUID() to parse UUID into object

Python Docs

Upvotes: 2

Related Questions