CODEWITHSUNDEEP
javaregex
dina
dina

Reputation: 4289

How to extract a string till the end of the line with regular expression

I have the following string(contains Portuguese characters) in the following structure: contain Name: and then some words after.

Example:

String myStr1 = "aaad  Name: bla and more blá\n gdgdf ppp";
String myStr2 = "bbbb  Name: Á different blÁblÁ\n hhhh fjjj";

I need to extract the string from 'Name:' till the end of the line. example:

extract(myStr1) = "Name: bla and more blá"
extract(myStr2) = "Name: Á different blÁblÁ"

Edit after @blue_note answer:

here is what I tried:

 public static String extract(String myStr) {
    Pattern p = compile("Name:(?m)^.*$");  
    Matcher m = p.matcher(myStr);

    while (m.find()) {
        String theGroup = m.group(0);
        System.out.format("'%s'\n", theGroup);
        return m.group(0);
    }
    return null;
}

did not work.

Upvotes: 2

Views: 9554

Answers (2)

blue note
blue note

Reputation: 29099

The regex is "^\\w*\\s*((?m)Name.*$)") where

  • ?m enables the multiline mode
  • ^, $ denote start of line and end of line respectively
  • .* means any character, any number of times

And get group(1), not group(0) of the matched expression

Upvotes: 4

Nitin
Nitin

Reputation: 916

You could also use substring in this case:

String name = myStr1.substring(myStr1.indexOf("Name:"), myStr1.indexOf("\n"));

Upvotes: 1

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