CODEWITHSUNDEEP
phpapistripe-payments
Andrew
Andrew

Reputation: 83

PHP Stripe API error on adding new card

im trying to add a new card to an existing customer and getting an error that i dont understand why it happens. here is a sample of the code:

$strp_customer  = \Stripe\Customer::retrieve($customer['stripe_id']);

echo $strp_customer->id;
echo "<br>";
echo $_POST['stripeToken'];
echo "<br>";
echo $strp_customer->default_source;
echo "<br>";
//save card to the customer in stripe
$strp_customer->source->create(array("source" => $_POST['stripeToken']));

echo $strp_customer->default_source;

the line with source create give me "Fatal error: Call to a member function create() on null"

but all echo return proper information. so the customer is retrieved and stripeToken is there. what can possibly cause that error?

Upvotes: 1

Views: 703

Answers (2)

vijay
vijay

Reputation: 729

Another solution with card details.

try {
        $customer = \Stripe\Customer::retrieve('cus_xxxxxxxxxxx');
        $card = $customer->sources->create(
            array(
                "source" => [
                    "object" => "card",
                    "name" => 'card holder name',
                    "number" => 'card number',
                    "cvc" => 'cvc',
                    "exp_month" => 'exp month',// E.g: 01,02...12
                    "exp_year" => 'exp year' // exp year
                ]
            )
        );
        echo ('Your card has been added successfully!');
    } catch (Exception $exception) {
        echo ('Unable to add new card, please enter valid card details.');
    }

Upvotes: 0

koopajah
koopajah

Reputation: 25652

This issue is a typo. The code should be 

$strp_customer->sources->create(array("source" => $_POST['stripeToken']));

It's sources and not source. You also need to make sure that you're on a recent version of the PHP library to support this call.

This will add a new card to the customer but won't set it as the default source. You're also not retrieving the customer again so you'd print the same value as before.

Upvotes: 1

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