Reputation: 5940
I have a dataframe df1
and each row of column A
contains a list of numbers like so:
import pandas as pd
dic = {'A':[[0,2,5,464,64789,131,13],[1,454,45166,78],[6,8],[1],[7,8789,45,65]]}
df1 = pd.DataFrame(dic)
My goal is to save each row in a .txt file so that it displays for each row the content of the list. So far I was able to achieve it by using the following line of code:
df1.to_csv('../ndb/_fede.txt',index=False, header=None)
However the output file has some quotation marks and brackets which I don't need.
# What I get | # What I WANT!
"[0, 2, 5, 464, 64789, 131, 13]" | 0,2,5,464,64789,131,13
"[1, 454, 45166, 78]" | 1,454,45166,78
"[6, 8]" | 6,8
"[1]" | 1
"[7, 8789, 45, 65]" | 7,8789,45,65
Basically what I want is that all numbers of each list are separated by a comma and no other characters.
Note: you can also take the df1
converted into arrays if needed.
Upvotes: 2
Views: 1567
Reputation: 294258
df1.A.apply(
lambda x: ','.join(pd.Series(x).astype(str))
).to_frame().to_csv('../ndb/_fede.txt', index=False, sep='|')
Upvotes: 1
Reputation: 862641
The simplier solution is cast to str
and remove []
by split
:
df1.A = df1.A.astype(str).str.strip('[]')
print (df1)
A
0 0, 2, 5, 464, 64789, 131, 13
1 1, 454, 45166, 78
2 6, 8
3 1
4 7, 8789, 45, 65
And if need remove whitespaces:
df1.A = df1.A.astype(str).str.strip('[]').str.replace('\s+', '')
print (df1)
A
0 0,2,5,464,64789,131,13
1 1,454,45166,78
2 6,8
3 1
4 7,8789,45,65
If need save only one column the simpliest is change default separator ,
, because separator ,
and values in column are ,
, so "
are added:
print (df1.to_csv(index=False, header=None, sep="|"))
0,2,5,464,64789,131,13
1,454,45166,78
6,8
1
7,8789,45,65
Upvotes: 4