CODEWITHSUNDEEP
regexvalidation
Dranzi666
Dranzi666

Reputation: 41

regex phone numbers separated with commas

i need a regular expression to validate the field. It is a field of phone numbers, the number consists of 9 characters, numbers will be separated by commas.

Example:

123456789,123456789,123456789
123456789
123456789,123456789

I have written: 

~^(([0-9]{9,9},)+|([0-9]{9,9})+)$~i

but validating passes only numbers with commas.

Example: 

123456789,123456789,
123456789,

Can you help me with this?

Upvotes: 1

Views: 1957

Answers (3)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626950

You need to set a * quantifier to the first 9-digit group:

~^(?:[0-9]{9},)*[0-9]{9}$~
               ^

See the regex demo. No need in ~i case insensitive modifier, there are no letters in the pattern. Also, {9,9} = {9}.

The same pattern can be written as

~^[0-9]{9}(?:,[0-9]{9})*$~

See another demo.

Details:

  • ^ - start of string
  • (?:[0-9]{9},)* - 0+ sequences of:
    • [0-9]{9} - 9 digits
    • , - comma
  • [0-9]{9} - 9 digits
  • $ - end of string (may be replaced with \z to match the very end of string).

EDIT: Since you only want to match comma-separated 9-digit chunks that only contain unique digits, it is possible to write a regex for that, although it is not recommended to use it. Best is to use your programming language means for that.

A regex will look like (verbose version):

^                      # start of string
 (                     # Group 1 start
  (\d)                 # Digit 1 captured into Group 2
  (?!\2)(\d)           # Digit 2 not equal to the first one
  (?!\2|\3)(\d)        # etc.
  (?!\2|\3|\4)(\d)
  (?!\2|\3|\4|\5)(\d)
  (?!\2|\3|\4|\5|\6)(\d)
  (?!\2|\3|\4|\5|\6|\7)(\d)
  (?!\2|\3|\4|\5|\6|\7|\8)(\d)
  (?!\2|\3|\4|\5|\6|\7|\8|\9)(\d)
 )
 (?:,(?1))*        # 0+ sequences of , and the Group 1 pattern
$                  # End of string

See the regex demo. A one-liner:

^((\d)(?!\2)(\d)(?!\2|\3)(\d)(?!\2|\3|\4)(\d)(?!\2|\3|\4|\5)(\d)(?!\2|\3|\4|\5|\6)(\d)(?!\2|\3|\4|\5|\6|\7)(\d)(?!\2|\3|\4|\5|\6|\7|\8)(\d)(?!\2|\3|\4|\5|\6|\7|\8|\9)(\d))(?:,(?1))*$

In PHP, you may just use 

if (count( array_unique( str_split( $s))) == strlen($s)) {
    echo "Unique";
} else {
    echo "Not unique";
}

Upvotes: 3

Angga
Angga

Reputation: 2323

Just move that plus(+) to the end of the bigger group

^(([0-9]{9,9},)|([0-9]{9,9}))+$

Upvotes: 0

Manuel Batsching
Manuel Batsching

Reputation: 3596

I don't think that your regex has to be very complicated:

^\d{9}(,\d{9})*,?
  • It will match at least one number block consisting of 9 digits.
  • Other 9 digit blocks might follow, if they are separated by a comma.
  • The whole expression can end with a comma.

Upvotes: 0

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