CODEWITHSUNDEEP
cstringfor-loopcs50
Nik
Nik

Reputation: 3

Trying to grab a character after a space in C

For an assignment I am doing, I have to print out the initials from a string in C (or, an array of characters). To do this, I know that I need to find where the SPACE is, using (int)name[i] == 32 to find if the current character is a SPACE. My only issue with this is that I am having trouble figuring out how I can find the space, and then store the next character in the array of character. (e.g., user enters Mike Baggins, I have to print out MB). I will post my code below, to show you how far I've gotten. Please help, but please don't give me the full solution. Thank you!

#include <cs50.h>
#include <stdio.h>
#include <string.h>

int main(void)
{
    string name = get_string(); // gets the user's input
    char firstI = name[0]; // stores the first character from the user's input
    int len = strlen(name);
    if((int)firstI >= 97 && (int)firstI <= 122) // checks if the character is lowercase
    {
        firstI -= 32; // makes the value uppercase
    }
    for(int i = 0; i < len; i++)
    {
        if((int)name[i] == 32) // checks if the character is SPACE
        {
            printf("I found a space!\n"); // prints out "I found a space"
        }
    }
    printf("%c\n", firstI); // prints out the first initial
}

Upvotes: 0

Views: 3231

Answers (1)

Iharob Al Asimi
Iharob Al Asimi

Reputation: 53016

It's actually simple, see this for example

#include <stdio.h>
#include <ctype.h>

int
main(void)
{
    char array[10];
    char string[] = "Mike Baggins";
    int j;
    // Always put the first non-whitespace 
    // character (we should probably skip all
    // spaces first
    array[0] = string[0];
    // Now start at the character following the first
    j = 1;
    for (int i = 1; ((string[i - 1] != '\0') && (j < sizeof(array) - 1)); ++i) {
        if (string[i - 1] == ' ') {
            array[j++] = toupper(string[i]);
        }
    }
    array[j] = '\0';
    puts(array);
    return 0;
}

All I needed was to know that strings are simply arrays with a special value marking the end of them → '\0'. Of course, you can improve it a lot. For instance, you could count how many initials are there in the input string and allocate enough space to store them all.

Also, this will only work if the interesting character follows the space immediately, but knowing that it's just an array I am sure you can figure out how to extend it to make it ignore consecutive spaces.

Upvotes: 2

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