Reputation: 1
I am trying to learn about python byte arrays to be able to write my own IP,TPC,UDP headers. I use the struct in python to pack and unpack binary data so the specified types given the format string.
ba2 = bytearray(2)
print(ba2, "The size: ", ba2.__len__())
struct.pack_into(">bx", ba2, 1, 1)
print(struct.unpack(">bx", ba2))
Now when I try to pack into a buffer of length 2 with ">bx"
as format, according to above code, I get the error:
bytearray(b'\x00\x00') The size: 2
Traceback (most recent call last):
File "D:/User/Documents/Python/Network/Main.py", line 58, in <module>
bitoperations_bytes_bytearrays_test()
File "D:/User/Documents/Python/Network/Main.py", line 49, in bitoperations_bytes_bytearrays_test
struct.pack_into(">bx", ba2, 1, 1)
struct.error: pack_into requires a buffer of at least 2 bytes
but I have a byte array of 2 bytes.
What am I doing wrong?
And please reference to some documentation, if I have missed it (I have read the python doc, but may have missed it).
Edit:
Sorry if I was unclear. but i want to just change the second byte in the byte array. Thus the 'x' padd in the format.
And as stupid as i was it is just to exclude the 'x' in the format like thiss:
struct.pack_into(">b", ba2, 1, 1)
and the right packing will have ben made. With this output:
bytearray(b'\x00\x00') The size: 2
A pack with one byte shift: 0001
(0, 1)
Upvotes: 0
Views: 4778
Reputation: 1
And as stupid as i was it is just to exclude the 'x' in the format like thiss:
struct.pack_into(">b", ba2, 1, 1)
and the right packing will have ben made. With this output:
bytearray(b'\x00\x00') The size: 2
A pack with one byte shift: 0001
(0, 1)
Upvotes: 0
Reputation: 456
You need one additional parameter for pack_into() function call. The third parameter is mandatory and it is offset in the target buffer (refer to https://docs.python.org/2/library/struct.html). Your format is also incorrect, because it just expects one byte. Following code fixes your problems:
import struct
ba2 = bytearray(2)
print(ba2, "The size: ", ba2.__len__())
struct.pack_into("bb", ba2, 0, 1, 1)
print(struct.unpack("bb", ba2))
Upvotes: 1