Reputation: 178
I'm trying to deserialize a class named CSound
public class CSound
{
public string id { get; set; }
public string name { get; set; }
public string file { get; set; }
public string fav { get; set; }
}
..from this XML
<?xml version="1.0" encoding="utf-8" ?>
<ArrayOfSounds xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<CSound>
<id>1</id>
<name>SampleName1</name>
<file>SampleFileName1</file>
<fav>true</fav>
</CSound>
<CSound>
<id>2</id>
<name>SampleName2</name>
<file>SampleFileName2</file>
<fav>false</fav>
</CSound>
<CSound>
<id>3</id>
<name>SampleName3</name>
<file>SampleFileName3</file>
<fav>true</fav>
</CSound>
<CSound>
<id>4</id>
<name>SampleName4</name>
<file>SampleFileName4</file>
<fav>false</fav>
</CSound>
<CSound>
<id>5</id>
<name>SampleName5</name>
<file>SampleFileName5</file>
<fav>true</fav>
</CSound>
</ArrayOfSounds>
T'm trying to deserialize using this section of code
Assembly assembly = typeof(App).GetTypeInfo().Assembly;
Stream stream = assembly.GetManifestResourceStream("SaynarSounds.Resources.XML.Sounds.xml");
List<CSound> sounds;
using (System.IO.StreamReader reader = new System.IO.StreamReader(stream))
{
XmlSerializer serializer = new XmlSerializer(typeof(List<CSound>));
sounds = (List<CSound>)serializer.Deserialize(reader);
}
if (sounds == null)
{
sounds = new List<CSound>();
}
return sounds;
Find the resource and start loading, but in deserialization I get this error:
System.InvalidOperationException: There is an error in XML document.
Can you help me?
UPDATE:
the exception throw this message
[ERROR] FATAL UNHANDLED EXCEPTION: System.InvalidOperationException: There is an error in XML document. ---> System.InvalidOperationException: was not expected 02-04 12:29:58.045 E/mono-rt ( 3046): at System.Xml.Serialization.XmlSerializationReaderInterpreter.ReadRoot (System.Xml.Serialization.XmlTypeMapping rootMap) [0x0005b] in /Users/builder/data/lanes/3511/501e63ce/source/mono/mcs/class/System.XML/System.Xml.Serialization/XmlSerializationReaderInterpreter.cs:182 02-04 12:29:58.045 E/mono-rt ( 3046): at System.Xml.Serialization.XmlSerializationReaderInterpreter.ReadRoot () [0x00028] in /Users/builder/data/lanes/3511/501e63ce/source/mono/mcs/class/System.XML/System.Xml.Serialization/XmlSerializationReaderInterpreter.cs:87 02-04 12:29:58.045 E/mono-rt ( 3046): at System.Xml.Serialization.XmlSerializer.Deserialize (System.Xml.Serialization.XmlSerializationReader reader) [0x0001c] in /Users/builder/data/lanes/3511/501e63ce/source/mono/mcs/class/System.XML/System.Xml.Serialization/XmlSerializer.cs:364
But I don't have an xmlns=''
.
Upvotes: 1
Views: 2554
Reputation: 117284
Your problem is that if you attempt to serialize a root object of type List<CSounds>
you will get XML like the following:
<ArrayOfCSound>
<CSound>
<id>one</id>
</CSound>
</ArrayOfCSound>
Notice that the root element <ArrayOfX>
ends in the same string X
as the nested item elements <X>
? This is inconsistent with your sample XML where the root element is named ArrayOfSound
but the item elements are named CSound
.
To work around this inconsistency, you will need to introduce a root type as follows:
[XmlRoot("ArrayOfSounds")]
public class CSoundsRoot
{
public CSoundsRoot() { this.Sounds = new List<CSound>(); }
[XmlElement("CSound")]
public List<CSound> Sounds { get; set; }
}
Then do:
XmlSerializer serializer = new XmlSerializer(typeof(CSoundsRoot))
var root = (CSoundsRoot)serializer.Deserialize(reader);
var sounds = root == null ? new List<CSounds>() : root.Sounds;
As an aside, bugs in XML deserialization can often be diagosed by serializing your type and comparing the observed XML with the expected XML.
Sample fiddle.
Upvotes: 1