Zea Lith
Zea Lith

Reputation: 421

update array of object without mutation

I'm following a react tutorial but I'm lost. I don't understand starting line 9.

enter image description here

so I tried to make a little miarature

const updateTodo = (list, updated) => {
   const index = list.findIndex(item => item.id === updated.id)
   return [
   ...list.slice(0,index),
   updated,
   ...list.slice(index+1)
   ]
}

https://jsbin.com/sifihocija/2/edit?js,console but failed to produce the result that the author did, what's wrong?

Upvotes: 9

Views: 9499

Answers (3)

Amir Baum
Amir Baum

Reputation: 25

For some reason the updated argument is an array, and therefore updated.id wont work. In that case, if you want to update the list item with that id the cleanest way to update list without mutating it would be to use Array.prototype.with() :

const updateTodo = (list, updated) => {
    const index = list.findIndex(item => item.id === updated[0].id);
    return list.with(index, updated[0]);
}

Upvotes: 0

Erfan Azary
Erfan Azary

Reputation: 864

It's simpler and cleaner using Array.map:

const updateTodo = (list, updated) =>
    list.map((item) => {
        if (item.id !== updated.id) {
            return item;
        }

        return updated;
    });

Upvotes: 1

Mayank Shukla
Mayank Shukla

Reputation: 104369

Issue is in this line:

const index = list.findIndex(item => item.id === updated.id)

updated is an array, to access the id, you need to specify the index also, for other array you are using loop, so item will be the each object of the array, and item.id will give you the id of each object, try this:

const index = list.findIndex(item => item.id === updated[0].id)

const arr = [
  {id:1,name:'hello'},
  {id:2,name:'hai'}
]

const arr2 = [
  {id:2,name:'this should be a new string'}
]

const updateTodo = (list, updated) => {
   const index = list.findIndex(item => item.id === updated[0].id);
   return [
   ...list.slice(0,index),
   ...updated,
   ...list.slice(index+1)
   ]
}

console.log(JSON.stringify(updateTodo(arr,arr2)))

Check the working code: https://jsbin.com/pazakujava/edit?js,console

Let me know if you need any help in this.

Upvotes: 11

Related Questions