CODEWITHSUNDEEP
pythonpython-2.7printingsleep
Dante Arcese
Dante Arcese

Reputation: 91

Delete Previous Line And Replace It With New Line?

My current code is the following:

for a in xrange (60, 0, -1):  
    b = "Sleeping for " + str(a) + " seconds\r"
    print b,
    sleep(1)

The only issue I have with it is that when it goes from 2 digit numbers to 1 digit numbers it prints secondss instead of seconds. How can I modify my code to properly replace the line when a goes from 2 digits to 1. Also, after the script is done printing the "Sleeping for __ seconds" lines am I able to replace that with a line that says "Sleeping for 60 seconds complete"

Upvotes: 0

Views: 753

Answers (3)

Uriel
Uriel

Reputation: 16184

How about using string formatting?

for a in xrange (60, 0, -1):  
    print "Sleeping for %2d seconds...\r" % a, 
    sleep(1)
print "Sleeping for 60 seconds complete!"

Upvotes: 0

erp
erp

Reputation: 555

you can print out an equal-length string of spaces to cover it up:

for a in xrange(60, 0, -1):
    out = "sleeping for {} seconds\r".format(a)
    sys.stdout.write(out)
    sys.stdout.flush()
    time.sleep(1)
    clear = " " * len(out)
    sys.stdout.write(clear + "\r")
print "Done"

you can also add ellipses to out to cover it up:

for a in xrange(60, 0, -1):
    out = "sleeping for {} seconds..\r".format(a)
    sys.stdout.write(out)
    sys.stdout.flush()
    time.sleep(1)
print "Done"

Upvotes: 0

Lajju
Lajju

Reputation: 11

You need to remove the comma in the print line to see the print output

Upvotes: 1

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