CODEWITHSUNDEEP
pythonlistdictionary
Yassine Belmamoun
Yassine Belmamoun

Reputation: 420

Order a dictionary based on specific values

Before writing a function, I would like to be sure there is no pre-built (optimized) solution (like sorted()) that can:

From a dictionary like this one :

tags = {'pinoyako':{'likes': 119, 'comments': 11, 'count': 1}, 'dii':{'likes': 151, 'comments': 3, 'count': 1},'djiphantom3':{'likes': 127, 'comments': 6, 'count': 1}}

Order the keys based on 'likes', 'comments' or 'count'. If it's based on 'likes', the output should be a list ordered :

output = [['dii',151],['djiphantom3',127],['pinoyako',119]]

Upvotes: 0

Views: 43

Answers (2)

Kasravnd
Kasravnd

Reputation: 107287

Use a generator expression within sorted() function with a proper key function:

In [22]: from operator import itemgetter
In [23]: sorted(((k, v['likes']) for k, v in tags.items()), key=itemgetter(1), reverse=True)
Out[23]: [('dii', 151), ('djiphantom3', 127), ('pinoyako', 119)]

Upvotes: 2

Mohammad Yusuf
Mohammad Yusuf

Reputation: 17054

You need more entries to illustrate. Check this:

tags = {'pinoyako':{'likes': 119, 'comments': 11, 'count': 1},
        'pinoyako2':{'likes': 120, 'comments': 5, 'count': 2},
        'djiphantom32':{'likes': 1275, 'comments': 61, 'count': 15},
        'dii2':{'likes': 151, 'comments': 33, 'count': 13},
        'dii':{'likes': 151, 'comments': 3, 'count': 1},
        'djiphantom3':{'likes': 1275, 'comments': 61, 'count': 1}
        }
tags_sorted = sorted(tags.items(), key=lambda x: (x[1]['likes'], x[1]['comments'], x[1]['count']))
tags_sorted

Output:

[('pinoyako', {'comments': 11, 'count': 1, 'likes': 119}),
 ('pinoyako2', {'comments': 5, 'count': 2, 'likes': 120}),
 ('dii', {'comments': 3, 'count': 1, 'likes': 151}),
 ('dii2', {'comments': 33, 'count': 13, 'likes': 151}),
 ('djiphantom3', {'comments': 61, 'count': 1, 'likes': 1275}),
 ('djiphantom32', {'comments': 61, 'count': 15, 'likes': 1275})]

Then you can do this:

tags_sorted = [[k, v['likes']] for k,v in tags_sorted]
tags_sorted

Output:

[['pinoyako', 119],
 ['pinoyako2', 120],
 ['dii', 151],
 ['dii2', 151],
 ['djiphantom3', 1275],
 ['djiphantom32', 1275]]

Upvotes: 0

Related Questions