The < div > filter in the < div > filter

Question

I have triangle, square, circle in red, blue, green and gold colors. I need to do filters for color and shapes. For example if I selected red color and circle I will see only one red circle This code HTML:

<table border="0">
<tr>
    <td width="20%" >
        <div id="triangleRed" class="color Red triangle"></div>
        <div id="triangleBlue" class="color Blue triangle"></div>
        <div id="triangleGreen" class="color Green triangle"></div>
        <div id="triangleGold" class="color Gold triangle"></div>
    </td>
   <td width="20%" align="center">
        <div id="squareRed" class="color Red square"></div>
        <div id="squareBlue" class="color Blue square"></div>
        <div id="squareGreen" class="color Green square"></div>
        <div id="squareGold" class="color Gold square"></div>
    </td>
    <td width="40%" align="center">
        <div id="circleRed" class="color Red circle"></div>
        <div id="circleBlue" class="color Blue circle"></div>
        <div id="circleGreen" class="color Green circle"></div>
        <div id="circleGold" class="color Gold circle"></div>
    </td>
    <td width="40%" >
        Filter:
        <br/>
        <div class="searchColor" id="filterColor">
            <div class="searchTextColor"> Color: </div>

            <input type="checkbox"  id="Red"  value="Red" />Red
            <br/>
            <input type="checkbox"  id="Blue"   value="Blue"/>Blue
            <br/>
            <input type="checkbox"  id="Green"  value="Green"/>Green
            <br/>
            <input type="checkbox" id="Gold"   value="Gold"/>Gold
            <p/>
        </div>
        <div class="searchColor" id="searchShape">
            <div class="searchShape"> Shape:</div>
            <div class="paintSelect">
                <input type="checkbox" id="triangle"  value="triangle" />triangle
                <br/>
                <input type="checkbox" id="circle"  value="circle"/>circle
                <br/>
                <input type="checkbox" id="square" value="square"/>square
            </div>
        </div>
    </td>
</tr>

And I has writen this code for filter:

$(document).ready(function() {

$("div[class='searchColor'] input").change(function () {
        var k = this.value;
    switch ($('input:checked').length) {

        case 0:
            $('.color').show();
            return;
        case 1:
            if (this.checked) {
                $('.color').hide();
            }
    }
    if($("div [class='paintSelect'] input").checked){
                    if (this.checked) {
                        $('.' + this.value).show();
                    } else {
                        $('.' + this.value).hide();
                    }
            }


    $('.' + this.value).toggle();

});
});

I recive this:https://jsfiddle.net/

But the code works not correctly. If you select color after that the shape or on the contrary. You can see the not correct answer. Where my misstake?

Answer 1

You need to consider 4 scenarios

1 : color & shape not selected

2 : color selected but not shape

3 : shape selected but not color

4 : both selected

Then either you can show all and hide not selected or hide all and show all selected i'm using the 1st way

  if($("#filterColor input:checked").length == 0 && $("#searchShape input:checked").length == 0){
        $('.color').show();
    }else if($("#filterColor input:checked").length == 0 && $("#searchShape input:checked").length > 0){
            $('.color').show();  
         $("#searchShape input:not(:checked)").each(function() {
                    $('.' + $(this).attr('value')).hide();
                    });
    }else if($("#filterColor input:checked").length > 0 && $("#searchShape input:checked").length == 0){
        $('.color').show();
      $("#filterColor input:not(:checked)").each(function() {
       //console.log(this,$(this).attr('value'),$('.'+$(this).attr('value')))
                    $('.' + $(this).attr('value')).hide();
                    });
    }else{
        $('.color').show();

       $("#searchShape input:not(:checked)").each(function() {
                    $('.' + $(this).attr('value')).hide();
                    });

         $("#filterColor input:not(:checked)").each(function() {
       //console.log(this,$(this).attr('value'),$('.'+$(this).attr('value')))
                    $('.' + $(this).attr('value')).hide();
                    });



    }

Fiddle is here https://jsfiddle.net/y2b3qebr/15/