Reputation: 43
[Working with R 3.2.2]
I have three data frames with the same variables. I need to modify the value of some variables and change the name of the variables (rename the columns). Instead of doing this data frame by data frame, I would like to use a loop.
This is the code I want to run:
#Change the values of the variables
vlist <- c("var1", "var2", "var3")
dataframe0[,vlist] <- dataframe0[,vlist]/10
dataframe1[,vlist] <- dataframe1[,vlist]/10
dataframe2[,vlist] <- dataframe2[,vlist]/10
#Change the name of the variables
colnames(dataframe0)[colnames(dataframe0)=="var1"] <- "temp_min"
colnames(dataframe0)[colnames(dataframe0)=="var2"] <- "temp_max"
colnames(dataframe0)[colnames(dataframe0)=="var3"] <- "prep"
colnames(dataframe1)[colnames(dataframe1)=="var1"] <- "temp_min"
colnames(dataframe1)[colnames(dataframe1)=="var2"] <- "temp_max"
colnames(dataframe1)[colnames(dataframe1)=="var3"] <- "prep"
colnames(dataframe2)[colnames(dataframe2)=="var1"] <- "temp_min"
colnames(dataframe2)[colnames(dataframe2)=="var2"] <- "temp_max"
colnames(dataframe2)[colnames(dataframe2)=="var3"] <- "prep"
I know the logic to do it with programs like Stata, with a forvalues loop:
#Change the values of the variables
forvalues i=0/2 {
dataframe`i'[,vlist] <- dataframe`i'[,vlist]/10
#Change the name of the variables
colnames(dataframe`i')[colnames(dataframe`i')=="var1"] <- "temp_min"
colnames(dataframe`i')[colnames(dataframe`i')=="var2"] <- "temp_max"
colnames(dataframe`i')[colnames(dataframe`i')=="var3"] <- "prep"
}
But, I am not able to reproduce it in R. How should I proceed? Thanks in advance!
Upvotes: 1
Views: 1729
Reputation: 15784
I would go working with a list of dataframe, you can still 'split' it after if really needed:
df1 <- data.frame("id"=1:10,"var1"=11:20,"var2"=11:20,"var3"=11:20,"test"=1:10)
df2 <- df1
df3 <- df1
dflist <- list(df1,df2,df3)
for (i in seq_along(dflist)) {
df[[i]]['test'] <- df[[i]]['test']/10
colnames( dflist[[i]] )[ colnames(dflist[[i]]) %in% c('var1','var2','var3') ] <- c('temp_min','temp_max','prep')
# eventually reassign df1-3 to their list value:
# assign(paste0("df",i),dflist[[i]])
}
The interest of using a list is that you can access them a little more easily in a programmatic way.
I did change your code from 3 calls to only one, as colnames
give a vector you can subset it and replace in one pass, this is assuming your var1 to var3 are always in the same order.
Addendum: if you want a single dataset at end you can use do.call(rbind,dflist)
or with data.table
package rbindlist(dflist)
.
More details on working with list of data.frames in Gregor's answer here
Upvotes: 1