CODEWITHSUNDEEP
javascript
jsc42
jsc42

Reputation: 117

2 return values in a function depending on if statement? (JS)

I want to create a function that takes in an array. If the array is empty (or === 0) I want to return one string. If the array is not empty, I want to return a different string + remove+return first element of array. How do I accomplish this?

Sample

> function(ary) {
> if (ary.length === 0) {
>-return string-
>}
>else {return other string + ary.shift[0]}
>}

Upvotes: 0

Views: 50

Answers (2)

ibrahim mahrir
ibrahim mahrir

Reputation: 31682

shift is a function that take no parameter. It should be called like this:

function(ary) {
    if (ary.length === 0) {
        return "string";
    }
    else {
        return "other string" + ary.shift();
    }
}

Note that the else could be removed. Just the return statment is enough since if the length of ary is 0 the code after if will never be reached (because of the return inside the if body), so the code after could be left unwrapped by the else. Like this:

function(ary) {
    if (ary.length === 0) // remove the braces as well since the `if` body is just one statement
        return "string";
    return "other string" + ary.shift(); // if `if`'s test is true this line will never be reached
}

Upvotes: 1

MaxZoom
MaxZoom

Reputation: 7753

Below is your code with one shift correction:

function check(ary) {
  if (ary.length === 0) {
    return "empty";
  } else {
    return "First was the " + ary.shift()
  }
}

console.log( check([]) );
console.log( check(['word', 'chaos', 'light']) );

Upvotes: 1

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