Reputation: 63
I'm creating a simple chat server as a personal project to learn net package and some concurrency in go. My 1st idea is to make the server print whatever is send using nc command echo -n "hello" | nc -w1 -4 localhost 2016 -p 61865
. However after the 1st read my code ignores the subsequent messages.
func (s *Server) messageReader(conn net.Conn) {
defer conn.Close()
buffer := make([]byte, 1024)
for {
//read buff
blen, err := conn.Read(buffer)
if err != nil {
log.Fatal(err)
}
message := string(buffer[:blen])
if message == "/quit" {
fmt.Println("quit command received. Bye.")
return
}
if blen > 0 {
fmt.Println(message)
buffer = buffer[:0]
}
}
}
// Run Start up the server. Manages join and leave chat
func (s *Server) Run() {
// Listen on port TCP 2016
listener, err := net.Listen("tcp", ":2016")
if err != nil {
log.Fatal(err)
}
defer listener.Close()
for {
//wait for connection
conn, err := listener.Accept()
if err != nil {
log.Fatal(err)
}
go s.messageReader(conn)
}
}
If I send a new message from a new client it prints without problems but if I send another one it does nothing. What am I missing do I need to reset the Conn or close it and spawn a new one?
Upvotes: 0
Views: 5135
Reputation: 109331
After printing your message, you slice buffer
down to zero length. You can't read any data into a zero-length slice. There's no reason to re-slice your read buffer at all.
You also need to handle the read bytes before checking for errors, as io.EOF
can be returned on a successful read.
You shouldn't use log.Fatal
in the server's read loop, as that calls os.Exit
A working messageReader
body might look like:
defer conn.Close()
buffer := make([]byte, 1024)
for {
n, err := conn.Read(buffer)
message := string(buffer[:n])
if message == "/quit" {
fmt.Println("quit command received. Bye.")
return
}
if n > 0 {
fmt.Println(message)
}
if err != nil {
log.Println(err)
return
}
}
You should note though that because you're not using any sort of framing protocol here, you can't guarantee that each conn.Read
returns a complete or single message. You need to have some sort of higher-level protocol to delimit messages in your stream.
Upvotes: 3